The surface area of the composite figure is 144 square cm after calculating separately.
<h3>What is a triangular prism?</h3>
When a triangle is, stretch it out to produce a stack of triangles, one on top of the other. A triangular prism is the name given to this novel 3D object.
We have a composite figure made up of a triangular prism and a cuboid
First we calculate the surface area of the triangular prism:
= 2(area of one triangle) + area of three rectangles
= 2[(1/2)6×4] + 3×5 + 3×5
= 24 + 15 + 15
= 54 square cm
Surface area of rectangle(with three faces) = 2(4×3 + 4×6) + 3×6
= 2(12 + 24) + 18
= 72 + 18 = 90 square cm
Total surface area of figure = 54+ 90 = 144 square cm
Thus, the surface area of the composite figure is 144 square cm after calculating separately.
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Answer:
C 3
Step-by-step explanation:
The equation is in the form y= mx+b, where m is the slope and b is the y intercept
y = 3x -14
The slope is 3 and the y intercept is -14
<span>–36, –32, –28, –24 This is an arithmetic sequence because each term has the same difference from the preceding term, called the common difference, d...
-32--36=-28--32=-24--28=4 So 4 is d, the common difference.
The sequence of any arithmetic sequence has the form:
a(n)=a+d(n-1), a=first term, d=common difference, n=term number...in this case we have:
a(n)=-36+4(n-1)
a(n)=-36+4n-4
a(n)=4n-40 so the 29th term is:
a(29)=4(29)-40
a(29)=116-40
a(29)=76
...
distance=velocity * time
d=vt we want to find t so
t=d/v and in this case:
t=234/70
t=(210+24)/70
t=3hr+(60*24)/70
t=3hr+20min+34sec so
t≈3hr 20min
...
This is an arithmetic sequence...100,150,200...
The sum of an arithmetic sequence will always be the average of the first and last terms times the number of terms....
the rule for the sequence is:
a(n)=a+d(n-1), a(n)=100+50d-50, a(n)=50n+50
Now we know the nth term is 50n+50, and we also know the first term is 100 so:
s(n)=n(100+50n+50)/2 and we want to know the sum of the first 10 terms so
s(10)=10(100+500+50)/2
s(10)=$3250
...
The first two terms are 2 and 4 so:
a(n)=2+2(n-1)
a(n)=2+2n-2
a(n)=2n
a(10)=20
...
You could do synthetic or long division, but you also could just use the fact that the factor being (x+8) should indicate a zero for the function when x=-8. If f(x) could be divided by (x+8) the value of y(-8) would equal zero, however calculating y(-8)=-10 so that would be the remainder if you did the division.</span>
That’s correct, as you’re reversing the positive on both sides for that number. Nice!
