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blondinia [14]
2 years ago
12

Please help! I filled in a little circle bc i thought it was right XDD

Mathematics
2 answers:
alisha [4.7K]2 years ago
6 0
That’s correct, as you’re reversing the positive on both sides for that number. Nice!
liq [111]2 years ago
6 0
1st one is right.

The 4th and 2nd ones are obviously wrong. And the 3rd one is wrong too because you can’t add 3 1/5, because your trying to get rid of it.
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Write an absolute value equation to satisfy the given solution set shown on a number line. PLEASE HELP
Darina [25.2K]

Answer: Ix - 4I ≤ 4

Step-by-step explanation:

You can see a black dot in the zero, and a black dot in the 8.

So those are the extremes of our set and are included in the set of solutions, we have that the set is defined by:

0 ≤ x ≤ 8.

Now we want to construct an absolute value equation such that the set {0 ≤ x ≤ 8} is the set of solutions.

The first step is to find the middle value of that set:

The middle value is equal to half of the difference between the extremes:

m = (8 - 0)/2 = 4.

Now we know the middle point, so we can write the equation:

Ix - mI ≤ m

m = 4

Ix - 4I ≤ 4

That is our inequality.

Where the "equal" part of ≤ is for the values x = 0 and x = 8.

8 0
3 years ago
Read 2 more answers
Suppose ten students in a class are to be grouped into teams. (a) If each team has two students, how many ways are there to form
ValentinkaMS [17]

Answer:

(a) There are 113,400 ways

(b) There are 138,600 ways

Step-by-step explanation:

The number of ways to from k groups of n1, n2, ... and nk elements from a group of n elements is calculated using the following equation:

\frac{n!}{n1!*n2!*...*nk!}

Where n is equal to:

n=n1+n2+...+nk

If each team has two students, we can form 5 groups with 2 students each one. Then, k is equal to 5, n is equal to 10 and n1, n2, n3, n4 and n5 are equal to 2. So the number of ways to form teams are:

\frac{10!}{2!*2!*2!*2!*2!}=113,400

For part b, we can form 5 groups with 2 students or 2 groups with 2 students and 2 groups with 3 students. We already know that for the first case there are 113,400 ways to form group, so we need to calculate the number of ways for the second case as:

Replacing k by 4, n by 10, n1 and n2 by 2 and n3 and n4 by 3, we get:

\frac{10!}{2!*2!*3!*3!}=25,200

So, If each team has either two or three students, The number of ways  form teams are:

113,400 + 25,200 = 138,600

6 0
3 years ago
Which situation can be represented by -35 + 35? Choose all that apply.
siniylev [52]

Answer: B & D

Step-by-step explanation:

In this scenario we want to come out with a situation where both sides are in an even playing field, as the equation solves to zero.

If a diver is 35 feet below water (-35) and he comes up to breathe, he goes up 35ft (35) meaning he is at the surface (0).

If Manuel is in debt for 35$ (-35) and then he pays off the 35$ (+35) then he is even (at 0).

4 0
3 years ago
Read 2 more answers
(9)(52)math question
lubasha [3.4K]

9 * 52 = (3 *3) * (2 * 2 * 13)

468

6 0
3 years ago
LESSON 3.2 (C) - Rates of Change and Slope
frozen [14]

Answer:

1. Slope = -2

2. Slope = ⁴/3

3. Slope = -3

4. Slope = 1

Step-by-step explanation:

1. Using two points on the line, (0, 0) and (-1, 2):

slope = \frac{y_2 - y_1}{x_2 - x1} = \frac{2 - 0}{-1 - 0} = \frac{2}{-1} = -2

2. Using two points on the line, (0, 0) and (3, 4):

slope = \frac{y_2 - y_1}{x_2 - x1} = \frac{4 - 0}{3 - 0} = \frac{4}{3}

3. Using two points on the line, (0, 0) and (-1, 3):

slope = \frac{y_2 - y_1}{x_2 - x1} = \frac{3 - 0}{-1 - 0} = \frac{3}{-1} = -3

4. Using two points on the line, (0, 0) and (2, 2):

slope = \frac{y_2 - y_1}{x_2 - x1} = \frac{2 - 0}{2 - 0} = \frac{2}{2} = 1

3 0
2 years ago
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