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riadik2000 [5.3K]
3 years ago
9

If there are 2,400 students, 52% are boys and 48% girls. What is the ratio of boy and girl?

Mathematics
2 answers:
anzhelika [568]3 years ago
8 0
Answer 13:12 I guess don’t fully believe me I worked it out and it was right but I may be wrong
jek_recluse [69]3 years ago
4 0

Answer:

13:12

Step-by-step explanation:

52% 2400 = 1248

48% 2400 = 1152

Reduce to 13/12 = 13:12

You might be interested in
Negative one-sixth of a number is less than -9. write an inequality.​
sladkih [1.3K]

Answer:

-1/6 n < -9

Step-by-step explanation:

Negative one-sixth of a number

-1/6 n

is less than -9

-1/6 n < -9

3 0
2 years ago
Use Part 1 of the Fundamental Theorem of Calculus to find the derivative of the function.
seropon [69]

Answer:

h'(x)=\frac{3r^{2}}{2\sqrt{r^3+5}}

Step-by-step explanation:

1) The Fundamental Theorem of Calculus in its first part, shows us a reciprocal relationship between Derivatives and Integration

g(x)=\int_{a}^{x}f(t)dt \:\:a\leqslant x\leqslant b

2) In this case, we'll need to find the derivative applying the chain rule. As it follows:

h(x)=\int_{a}^{x^{2}}\sqrt{5+r^{3}}\therefore h'(x)=\frac{\mathrm{d} }{\mathrm{d} x}\left (\int_{a}^{x^{2}}\sqrt{5+r^{3}}\right )\\h'(x)=\sqrt{5+r^{3}}\\Chain\:Rule:\\F'(x)=f'(g(x))*g'(x)\\h'=\sqrt{5+r^{3}}\Rightarrow h'(x)=\frac{1}{2}*(r^{3}+5)^{-\frac{1}{2}}*(3r^{2}+0)\Rightarrow h'(x)=\frac{3r^{2}}{2\sqrt{r^3+5}}

3) To test it, just integrate:

\int \frac{3r^{2}}{2\sqrt{r^3+5}}dr=\sqrt{r^{3}+5}+C

5 0
2 years ago
Please help me with this math problem
ollegr [7]

10 \times 5 +  \frac{ {4}^{2} }{4}  = 50 + 4 = 54
8 0
3 years ago
Suppose a large shipment of laser printers contained 18% defectives. If a sample of size 340 is selected, what is the probabilit
lukranit [14]

Answer:

The probability that the sample proportion will be greater than 13% is 0.99693.

Step-by-step explanation:

We are given that a large shipment of laser printers contained 18% defectives. A sample of size 340 is selected.

Let \hat p = <u><em>the sample proportion of defectives</em></u>.

The z-score probability distribution for the sample proportion is given by;

                         Z  =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n}}  }  ~ N(0,1)

where, p = population proportion of defective laser printers = 18%

            n = sample size = 340

Now, the probability that the sample proportion will be greater than 13% is given by = P(\hat p > 0.13)

         P(\hat p > 0.13) = P( \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n}}  } > \frac{0.13-0.18}{\sqrt{\frac{0.13(1-0.13)}{340}}  } ) = P(Z > -2.74) = P(Z < 2.74)

                                                                      = <u>0.99693</u>

The above probability is calculated by looking at the value of x = 2.74 in the  table which has an area of 0.99693.

7 0
2 years ago
Pls help hurry giving 20 points
Likurg_2 [28]

Answer:

always, values, forms, an unlimited number of

Step-by-step explanation:

brainliest?

3 0
2 years ago
Read 2 more answers
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