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1 year ago

Ask me a random question

Mathematics

1 answer:

AleksAgata [21]1 year ago

8 0

Answer:

Step-by-step explanation:

why do pokemon have typeings

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Larry buys a tent that is on sale for 25% off the original price. The original price is $80 more than the sale price. What is th

myrzilka [38]

Answer:

The original price of the tent = $320

Step-by-step explanation:

Let the original price be =$ $x$

Discount offered = $25$ % of the orignal price = $\frac{25}{100}\times x=0.25\times x =\$ 0.25x$

Original price is $80 more than sale price

Discount = Original price - Sale price = $80

So, we have

$0.25x=80$

We need to solve for $x$ to find original price

Dividing both sides by $0.25$

$\frac{0.25}{0.25}x=\frac{80}{0.25}\\x=\$320$

∴ The original price of the tent = $320

3 0

3 years ago

Deisha can build a fence in 15 hours, and Travis can build a fence in 12 hours. How long will it take them together to build a f

Basile [38]

Answer:

6 $\frac{2}{3}$

Step-by-step explanation:

Deisha's build rate = 1 fence per 15 hours = 1/15 fences per hour

Travis's build rate = 1 fence per 12 hours = 1/12 fences per hour

Working together, their combined rate is 1/15 + 1/12 = 3/20 fences per hour

So it takes them 20/3 = 6 2/3 hours per fence

6 0

3 years ago

Pls show full working out

sweet-ann [11.9K]

Answer:

Question 1a. i) $x=1.8m$

Question 1a. ii) $Volume=27.6m^3$

Question 1b) $Volume=65.9m^3$

Explanation:

Question 1 a. i) Find the value of x.

$tan(\theta )=\dfrac{opposite\text{ }leg}{adjacent\text{ }leg}$

For the smalll triangle you can write:

$tan(\theta )=\dfrac{x}{1m}$

For tthe big triangle:

$tan(\theta )=\dfrac{x+2.7m}{2.5m}$

Substitute:

$\dfrac{x}{1m}=\dfrac{x+2.7m}{2.5m}$

Solve for x:

$2.5x=x+2.7m\\\\2.5x-x=2.7m\\\\1.5x=2.7m\\\\x=2.7m/1.5\\\\x=1.8m$

Question 1a ii) Find the volume of the frustrum

Find the volume of a cone with height = 2.7m + 1.8m = 4.5m, and radius = 2.5m

Formula:

$Volume=(1/3)\pi \times radius^2\times height$

Substitute:

$Volume=(1/3)\pi \times (2.5m)^2\times 4.5m=9.375\pi m^3$

Find the volume of a cone with heigth = 1.8m and radius = 1m

$Volume=(1/3)\pi \times (1m)^2\times 1.8m=0.6\pi m^3$

Subtract the volume of the small cone from the volume of the big cone

$Volume\text{ }of\text{ }frustrum=9.375\pi m^3-0.6\pi m^3=8.775\pi m^3\approx 27.6m^3$

Question 1b. Calculate the volume of the bin

i) Upper frustrum

This is the same frustrum from the equation of above, thus ist volume is 27.6m³.

ii) Lower frustrum

$\dfrac{x}{2.0m}=\dfrac{x+2.4m}{2.5m}$

$2.5x=2(x+2.4m)\\\\2.5x=2x+4.8m\\\\0.5x=4.8m\\\\x=9.6m$

$Volume=(1/3)\pi \times (2.5m)^2\times (9.6m+2.4m)-(2.0m)^2\times (9.6m)$

$Volume=38.3m^3$

iii) Add the volume of the two frustrums

$Volume=27.6m^3+38.3m^3=65.9m^3$

6 0

3 years ago

Which set of points lie on the given graph?

maks197457 [2]

The answer is B (3, 9), (1,-5), (3,3)

3 0

3 years ago

Read 2 more answers

2r/5+7r/15= rewrite the expression by collecting like terms

kramer

2r/5+7r/15=
LCM=15
(15\5=3*2r=6r)
15\15=1*7r=7r
answer=6r+7r\15
answer=13r\15

3 0

3 years ago

Read 2 more answers