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9966 [12]
1 year ago
7

A recent survey on movies found that 1 out of 6 students likes comedy films. Graph the relationship between the total number of

students and the students who like comedy films for different number of students given in the table below.
Total Number of Students​ 90​ 180​ 270​ 360​
Mathematics
1 answer:
lakkis [162]1 year ago
6 0

Probability of people liking comedy movies = 1/6

Hence,

If total number of people are 90, then the number of people liking comedy movies = 90/6 = 15

If total number of people are 180, then the number of people liking comedy movies = 180/6 = 30

If total number of people are 270, then the number of people liking comedy movies = 270/6 = 45

If total number of people are 360, then the number of people liking comedy movies = 360/6 = 60

Let the x-axis represent the total number of people and,

The y-axis represent the number of people liking comedy films.

The function will be :-

f(x) = x/6 , where x is the total number of people.

The graph is attached.

Download pdf
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How to solve this problem?
valentinak56 [21]

Very nice handwriting but the math and English are confusing.

Let's assume we're told

\displaystyle 45 = \sum_{i=1}^9 (x_i - 10)^2

The subscript is important.

I think we're told the similar sum with 11 gives the smallest possible value for the sum. This is a rather cagey way of telling us 11 is the mean of the nine points. The mean is the number which minimizes the sum of squared deviations.

\displaystyle 45 = \sum_{i=1}^9 (x_i - 10)^2 = \sum x_i^2 - 20 \sum x_i + 9(100)

\displaystyle  \sum x_i^2=  20 \sum x_i  - 900

If 11 is the mean, the sum of the points is 9(11)=99.

\displaystyle  \sum x_i^2=  20 (99)  - 900 = 1080

Answer: 1080

6 0
4 years ago
Calificación mínima. Para obtener una A en un curso, Stephen Heasley debe
Snowcat [4.5K]

Answer:

La mínima calificación que Stephen puede recibir en el quinto examen  para obtener una A en el curso es 98.

Step-by-step explanation:

La media (también llamada promedio o media aritmética) de un conjunto de datos es una medida de posición central. Es el valor obtenido al sumar todos los datos y dividir el resultado entre el número total de datos.

En este caso, el número total de datos es 5 y el valor de los datos de los cuales debes obtener el problema es 92, 87, 96, 77 y un valor desconocido de un quinto examen. Y sabes que este valor debe ser igual o mayor a 90.

Esto se expresa matemáticamente como:

\frac{92+87+96+77+nota}{5}≥90

donde "nota" es la mínima calificación que Stephen puede recibir en el quinto examen para obtener una A en el curso.

Resolviendo:

\frac{352+nota}{5}≥90

352+nota≥90*5

352+nota≥450

nota≥450 - 352

nota≥98

<u><em>La mínima calificación que Stephen puede recibir en el quinto examen  para obtener una A en el curso es 98.</em></u>

3 0
3 years ago
Please help!! ill give brainliest + points!!
zheka24 [161]

Answer:

A

Step-by-step explanation:

6 0
3 years ago
Will give brainliest and 5 starsPLEASE HELP
Ymorist [56]

Answer:

The slope of AB is undefined; the slope of CD is 0; The lines are perpendicular.

Step-by-step explanation:

Line AB would form a vertical line. Slope is Δy/Δx. To go from 3 to 7 (the y-coordinates) you need to go up 4 units. So we would then have Δy/Δx = 4/Δx. To go from -5 to -5 (the x-coordinates) we have to go left or right 0 units. So, Δy/Δx = 4/Δx = 4/0. Anything divided by 0 is undefined. <em>Remember: vertical lines always have an undefined slope.</em>

Line CD would form a horizontal line. To go from 9 to 9 (the y-coordinates) you need to go up or down 0 units. So, Δy/Δx = 0/Δx. To go from 1 to -10 (the x-coordinates) you need to go down 11 units. So Δy/Δx = 0/Δx = 0/1. 0 divided by anything is 0. <em>Remember: horizontal lines always have a slope of 0.</em>

If you picture a horizontal line and a vertical line intersecting, they would both form a right angle when they intersect.  By definition, this would make both lines perpendicular.

8 0
3 years ago
Read 2 more answers
Two options are described below.
ICE Princess25 [194]
I would receive 100 each day
4 0
3 years ago
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