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Aleks [24]
1 year ago
8

Haroon went to the mall with $50 in his bank account. He bought a pair of jeans for $39.995. The cashier gave him $2.49 in chang

e. How much money should Haroon received from his purchase?
Mathematics
2 answers:
lana [24]1 year ago
8 0

Answer:

I think the answer is $10.005

Step-by-step explanation:

50-39.995=10.005

Ivenika [448]1 year ago
3 0
He should’ve gotten $10.05
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If AB = 13, BC = 9, and CA = 17, list the angles in order from smallest to largest.
Licemer1 [7]
A,C,B
This is the answer;BC,AB,CA
8 0
4 years ago
If x, y, and z are integers greater than 1, and (327)(510)(z) = (58)(914)(xy), then what is the value of x? (1) y is prime (2) x
Virty [35]

Answer:

1) 5

2) 5

Step-by-step explanation:

Data provided in the question:

(3²⁷)(5¹⁰)(z) = (5⁸)(9¹⁴)(x^y)

Now,

on simplifying the above equation

⇒ (3²⁷)(5¹⁰)(z) = (5⁸)((3²)¹⁴)(x^y)

or

⇒  (3²⁷)(5¹⁰)(z) = (5⁸)(3²⁸)(x^y)

or

⇒ (\frac{3^{27}}{3^{28}})(\frac{5^{10}}{5^8})z=x^y

or

⇒(\frac{5^2}{3})z=x^y

or

⇒\frac{5^2}{3}=\frac{x^y}{z}

we can say

x = 5, y = 2 and, z = 3

Now,

(1) y is prime

since, 2 is a prime number,

we can have

x = 5

2) x is prime

since 5 is also a prime number

therefore,

x = 5

8 0
3 years ago
Convert 9 over 4 into mixed numbers
Maslowich
9/4
well, 4 times 2 is 8, there would be a quarter left over
answer: 2 1/4

so it would be 2 and a quarter.

Hope this helped :)


6 0
4 years ago
A box contains 8 two-inch screws. Four have a Phillips head and 4 have a slotted head. In how many ways can 4 screws be chosen s
hammer [34]

Answer:

There are 6\cdot 6=36 different ways to choose 4 screws such that 2 have a Phillips head and 2 have a slotted head.

Step-by-step explanation:

If 4 screws must be chosen so that 2 have a Phillips head and 2 have a slotted head, then you have to choose 2 screws with a Phillips head from 4 screws with a Phillips head and 2 screws with a slotted head from 4 screws with a slotted head.

You can choose 2 screws with a Phillips head from 4 screws with a Phillips head in

C^4_2=\dfrac{4!}{2!(4-2)!}=\dfrac{4!}{2!\cdot2!}=\dfrac{1\cdot2\cdot3\cdot4}{1\cdot2\cdot1\cdot2}=6

different ways.

You can choose 2 screws with a slotted head from 4 screws with a slotted head in

C^4_2=\dfrac{4!}{2!(4-2)!}=\dfrac{4!}{2!\cdot2!}=\dfrac{1\cdot2\cdot3\cdot4}{1\cdot2\cdot1\cdot2}=6

different ways.

In total there are 6\cdot 6=36 different ways to choose 4 screws such that 2 have a Phillips head and 2 have a slotted head.

7 0
3 years ago
ASAP HURRY! WILL UPVOTE YOUR ANSWER PLEASEANSWER THIS CORRECTLY
DaniilM [7]

Answer:

-35/40, -3/8, 81, 81.125

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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