All categories

4 years ago

It would be really helpful if you could solve this for me. Please and thank you:)

Mathematics

1 answer:

katrin2010 [14]4 years ago

3 0

Hey there! :)

Answer:

2nd choice.

Step-by-step explanation:

Given:

630 = 42f.

Divide both sides by 42 to solve for f:

630/42 = 42f/42

f = $15.

This equation is not an inequality, so a line would not be graphed on the number-line. The proper way to show a single solution would be with a point. Therefore:

The second choice is correct. The number line has a single point at f = 15.

You might be interested in

An investment account earns 4% per year compounded annually. If the initial investment was $4,000.00, how much is in the account

Alisiya [41]

The account is $4,480 after 3 years with a 4% investment

3 0

3 years ago

What is the area of this face?

BARSIC [14]

Answer:

10*4-6*2=28

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

I don’t know how to do this one.

serious [3.7K]

Answer:

(a) The unit circle is centered at (0,0) with a radius of 1.

(b) The equation of a circle of radius r, with a center located at (0,0):

x²+ y² = r².

(ii) P(0,1)

(iii) P(-1,0)

(iv) P(0,-1)

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Express 4x^-4 with a positive exponent.

Mumz [18]

Answer:

4x^-4

4(x^-2)²

4x^4

Step-by-step explanation:

sorry I am not clear about question.

6 0

3 years ago

The average estimated hours a person in the United States spent playing video games per year from 2002 to 2012 were 71, 80, 82,

ozzi

Answer:

Population variance 579

Population standard deviation 24

Step-by-step explanation:

The average estimated hours a person in the United States spent playing video games per year from 2002 to 2012 were 71, 80, 82, 78, 80, 91, 107, 121, 125, 131, and 142.

The population variance is given by:

$\sigma^2=\frac{\sum(x-\mu)^2}{n}$

$\mu=\frac{71+80+82+78+80+91+107+121+125+131+142}{11}$

$\mu=\frac{1108}{11}$

This implies that:

$\sigma^2=\frac{(71-\frac{1108}{11})^2+(80-\frac{1108}{11})^2+(82-\frac{1108}{11})^2+(78-\frac{1108}{11})^2+(80-\frac{1108}{11})^2+...+(142-\frac{1108}{11})^2}{11}$

$\sigma^2=\frac{70006}{121} =579$ to the nearest whole number

The population standard deviation is

$\sigma=\frac{\sqrt{70006} }{11}=24$ to the nearest whole number.

3 0

3 years ago

Read 2 more answers