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wolverine [178]
3 years ago
8

PLEASE HELP

Mathematics
2 answers:
kogti [31]3 years ago
7 0
\textbf{You have to} restrict the domains of quadratic functions and absolute value functions, because these functions are \textbf{many-to-one} functions. For instance, the quadratic function f(x) = x^2 pairs both −2 and 2 with 4, and the absolute value function f(x) = |x| pairs both −2 and 2 with 2.

Linear functions (excluding constant functions) and exponential functions are \textbf{one-to-one} functions, so their domains \textbf{do not need} to be restricted.
_________________

An absolute value function, without domain restriction, has an inverse that is NOT a function.

In order to guarantee that the inverse must also be a function, we need to restrict the domain of the absolute value function to make it a one-to-one function.
Otrada [13]3 years ago
5 0

Answer:

restrict the domains of quadratic functions and absolute value functions, because these functions are  functions. For instance, the quadratic function f(x) = x^2 pairs both −2 and 2 with 4, and the absolute value function f(x) = |x| pairs both −2 and 2 with 2.

Step-by-step explanation:

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8 sides

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the sum of the exterior angles of a polygon = 360°

number of sides = \frac{360}{45} = 8


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Step-by-step explanation:

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Help! I really need to pass!
Dmitriy789 [7]

Answer:

\huge{ \boxed{ \bold{ \sf{y =  - 2x + 6}}}}

☥ \tt{Question} :

  • Write the equation of a line in slope - intercept form that has a slope of -2 and passes through the point ( - 1 , 8 ).

☥ \tt{Step  -  \: by \:  -  \: step \: explanation}

☪ \underline{ \underline{ \text{Given : }}}

  • Slope ( m ) = -2
  • Given point = ( - 1 , 8 )

☪ \underline {\underline{ \text{To \: find}}} :

  • Equation of a line in slope - intercept form ( i.e y = mx + c )

Let the point ( -1 , 8 ) be ( x₁ , y₁ )

☪ \underline{ \underline{ \text{Solution}}} :

\underline{ \sf{y - y1 = m(x - x1)}}

plug the known values :

↦ \text{y - 8 =  - 2 \{ x - ( - 1) \} }

↦ \text{y - 8 =  - 2(x + 1)}

Distribute -2 through the parentheses :

↦ \text{y - 8 =  - 2x - 2}

Transpose 8 to right hand side and change it's sign

↦ \text{y =  - 2x - 2 + 8}

↦ \boxed{ \text{y =  - 2x + 6}}

And we're done !

Hope I helped!

♡ Have a wonderful day / night ツ

~TheAnimeGirl ♪

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4 0
3 years ago
Read 2 more answers
Which expression is not a polynomial?
solmaris [256]

Answer:

B.

Step-by-step explanation:

For an expression to be a polynomial , it must contain no square roots of variables, no fractional or negative powers on the variables, and no variables in the denominators of any fractions.

7 0
3 years ago
Read 2 more answers
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