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hjlf
11 months ago
8

Matt's Cafe offers two kinds of espresso: single-shot and double-shot. Yesterday afternoon,

Mathematics
2 answers:
Lina20 [59]11 months ago
8 0

Answer: 48%

Step-by-step explanation:

scale up,

24/50=x/100

multiply 24/50 by 2 to get 100

so you get 48/100 which is 48%

timama [110]11 months ago
4 0

Answer:

57 I think I'm not entirely sure

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Dana walks 3/5 mile in 1/4 hour. What is dana's walking rate in miles per hour?
Flura [38]
Here, our equation is 3/5 (0.6) mile per 1/4 (0.25) hour.  0.25 times 4 = 1, so we have to multiply 1/4 (0.25) 4 times to get 1 mile. To get a proportional answer, we must also multiply 3/5 (0.6) by 4. This comes out to 2.4. So her walking rate is 2.4 miles per hour.


8 0
3 years ago
The position of an open-water swimmer is shown in the graph. The shortest route to the shoreline is one that is perpendicular to
Stolb23 [73]

Answer:

Step-by-step explanation:

To define the perpendicular line we need to first know the slope of the reference line graphed.

m=(y2-y1)/(x2-x1) we have points (0,5) and (2,1)

m=(1-5)/(2-0)

m=-4/2

m=-2

For lines to be perpendicular their slopes must satisfy

m1m2=-1, we have a line with a slope of -2 so

-2m=-1

m=1/2, so our perpendicular line is so far

y=x/2+b, it must have point (3,2) so we can solve for b

2=3/2+b

b=1/2, so the swimmer will travel along the line

y=x/2+1/2

6 0
3 years ago
the perimeter of one rectangle is 120cm. another rectangle with twice the length amd and one third the width has a perimeter of
fgiga [73]

Answer:

Dimensions of 1st rectangle,

length = 39 cm, width = 21 cm.

Dimensions of the 2nd rectangle,

length = 78 cm, width = 7 cm.

Step-by-step explanation:

Let the dimensions of the 1st rectangle be,

Length = x, width = y

so the dimensions of the 2nd rectangle becomes,

Length = 2x, width = y/3

perimeter of the first rectangle,

2(x+y)=120 --------- (i)

perimeter of the 2nd rectangle,

2(2x+y/3)=170 ---------(ii)

if we solve equation (i) and (ii), we'll get,

x = 39

y = 21

for the other rectangle, 2x = 78, y/3 = 7.

Answered by GAUTHMATH

3 0
3 years ago
If 8 identical blackboards are to be divided among 4 schools,how many divisions are possible? How many, if each school mustrecei
MAXImum [283]

Answer:

There are 165 ways to distribute the blackboards between the schools. If at least 1 blackboard goes to each school, then we only have 35 ways.

Step-by-step explanation:

Essentially, this is a problem of balls and sticks. The 8 identical blackboards can be represented as 8 balls, and you assign them to each school by using 3 sticks. Basically each school receives an amount of blackboards equivalent to the amount of balls between 2 sticks: The first school gets all the balls before the first stick, the second school gets all the balls between stick 1 and stick 2, the third school gets the balls between sticks 2 and 3 and the last school gets all remaining balls.

 The problem reduces to take 11 consecutive spots which we will use to localize the balls and the sticks and select 3 places to put the sticks. The amount of ways to do this is {11 \choose 3} = 165 . As a result, we have 165 ways to distribute the blackboards.

If each school needs at least 1 blackboard you can give 1 blackbooard to each of them first and distribute the remaining 4 the same way we did before. This time there will be 4 balls and 3 sticks, so we have to put 3 sticks in 7 spaces (if a school takes what it is between 2 sticks that doesnt have balls between, then that school only gets the first blackboard we assigned to it previously). The amount of ways to localize the sticks is {7 \choose 3} = 35. Thus, there are only 35 ways to distribute the blackboards in this case.

4 0
3 years ago
Can someone answer 33 please?!
Temka [501]
(x)+(x+1)+(x+2)=228.

3x+3=228
3x=225
x=75
Integer 1: 75
Integer 2: 76
Integer 3: 77

75+76+77=228

8 0
2 years ago
Read 2 more answers
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