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2 years ago

Please help due soon

Mathematics

1 answer:

ElenaW [278]2 years ago

7 0

Answer:

$4742.10

Step-by-step explanation:

Exponential depreciation formula :-

, where y is the value of good after t years , r is rate of depreciation and A is the initial value.

Given : A= $20800 ; r=10.75%=0.1075

The equation models this situation:

Then, the value of car after t=13 years :-

Hence, the value of car after 13 years = $4742.10

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The length of an edge of a cube is 2 inches. How many cubic inches are there in the volume of the cube ?

gizmo_the_mogwai [7]

A cube has equal edges, so 2*2*2 or 2^3 (2 cubed) v=8^3

4 0

3 years ago

A clock was reading the time accurately on Friday at noon. On Monday at 6pm the clock was running late by 468 seconds. On averag

Setler [38]

The clock was skipping 3 seconds every 30 minutes from Friday noon to Monday 6 pm.

The clock was still accurate by Friday noon. The clock was late by 468 seconds by Monday, 6 pm.

To solve the problem, we must:

Know how many 30-minutes have passed during the time period.

1 day = 24 hours

1 hour = 60 minutes = 2 × (30 minutes)

1 day = 24 hours × 2 × (30 minutes)

1 day = 48 × (30 minutes)

Thus, there are 48, 30-minutes in a day. On Friday, however, we start counting at noon, which is half of the day. Moreover, on Monday, the mark is only up to 6 pm, which is three-fourths of the day.

Friday = 48 × $\frac{1}{2}$ = 24

Saturday = 48

Sunday = 48

Monday = 48 × $\frac{3}{4}$ = 36

TOTAL = 24 + 48 + 48 + 36 = 156

Therefore, the total number of 30-minutes that have passed is 156. There were 156, 30-minutes that passed during the time period.

Divide the number of total seconds late by the number of 30-minutes passed.

That is, the number of total seconds late= 468 seconds ÷ 156

= 3 seconds

Therefore, the clock was skipping 3 seconds every 30 minutes from Friday noon to Monday 6 pm.

To learn more about clock problems visit:

brainly.com/question/27122093.

#SPJ1

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2 years ago

What is the area of the composite figure

oksano4ka [1.4K]

Answer:

Step-by-step explanation:

To find the area of a composite figure, separate it into the regular parts which make the irregular shape. This shape is composed of a semi-circle and a rectangle. Find the area by finding the area of each shape.

Semi-circle:

The semi-circle has a diameter of 2 + 4 + 2 = 8. The area this figure uses the radius which is half the diameter. The radius is 4. To find the area substitute r = 4 into $\pi r^2 = \pi 4^2 = 16\pi$ . However the semi-circle has a smaller circle cut out of it with radius 2. The area of the smaller circle is $\pir^2 = \pi 2^2=4\pi$ . The semi circle in the shape is the areas subtracted which equals 12π.