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3 years ago

For every 144 light bulbs produced, 6 are defective. Find the number of defective light bulbs that could be expected out of 720.

2 answers:

7 0

You are going to get the rate of the detects.
6 detects ÷ 114 light bulbs = 1/19 detects per light bulb

If there are 720 light bulbs, then the number of detects will be
720 light bulbs * 1/19 detects per light bulb = 37. 89 ≈ 38 detects

torisob [31]3 years ago

6 0

Answer:

Step-by-step explanation:

your welcome

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ad-work [718]

It's not difficult to compute the values of $A$ and $B$ directly:

$A=\displaystyle\int_1^{\sin\theta}\frac{\mathrm dt}{1+t^2}=\tan^{-1}t\bigg|_{t=1}^{t=\sin\theta}$
$A=\tan^{-1}(\sin\theta)-\dfrac\pi4$

$B=\displaystyle\int_1^{\csc\theta}\frac{\mathrm dt}{t(1+t^2)}=\int_1^{\csc\theta}\left(\frac1t-\frac t{1+t^2}\right)\,\mathrm dt$
$B=\left(\ln|t|-\dfrac12\ln|1+t^2|\right)\bigg|_{t=1}^{t=\csc\theta}$
$B=\ln\left|\dfrac{\csc\theta}{\sqrt{1+\csc^2\theta}}\right|+\dfrac12\ln2$

Let's assume $0$ , so that $|\csc\theta|=\csc\theta$ .

Now,

$\Delta=\begin{vmatrix}A&A^2&B\\e^{A+B}&B^2&-1\\1&A^2+B^2&-1\end{vmatrix}$
$\Delta=A\begin{vmatrix}B^2&-1\\A^2+B^2&-1\end{vmatrix}-e^{A+B}\begin{vmatrix}A^2&B\\A^2+B^2&-1\end{vmatrix}+\begin{vmatrix}A^2&B\\B^2&-1\end{vmatrix}$
$\Delta=A(-B^2+A^2+B^2)-e^{A+B}(-A^2-A^2B-B^3)+(-A^2-B^3)$
$\Delta=A^3-A^2-B^3+e^{A+B}(A^2+A^2B+B^3)$

There doesn't seem to be anything interesting about this result... But all that's left to do is plug in $A$ and $B$ .

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FrozenT [24]

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A rectangular tank measures 20cm x 30cm x 40cm. You want to fill it by using a cubic container that is 20cm on each side to carr

umka2103 [35]

Answer:

4 trips

Step-by-step explanation:

Given that:

Dimension of rectangular tank :

(20cm * 30cm * 40cm)

Dimension of cubic container used to fill tank = 20cm per side

Volume of tank = (20 * 30 * 40) = 24400 cm³

Volume of cubic container = (20 * 20 * 20) = 8000 cm³

Number of trips it would take :

Volume of tank / volume of container

24400 cm³ / 8000 cm³

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