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shtirl [24]
3 years ago
9

Find the surface area of the solid. Round to two decimal places

Mathematics
1 answer:
Ne4ueva [31]3 years ago
5 0
Check the picture below.

so, to get the area of the triangles, we can simply run a perpendicular line from the top to the base, and end up with a right-triangle with a base of 22 and a hypotenuse of 34, let's find the altitude.

\bf \textit{using the pythagorean theorem}
\\\\
c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
\sqrt{34^2-22^2}=b\implies \sqrt{672}=b

so then the surface area of the triangular prism is,

\bf \stackrel{\textit{left and right}}{2(34\cdot 76)}~~+~~\stackrel{\textit{bottom}}{(44\cdot 76)}~~+~~\stackrel{\textit{front and back}}{2\left[\cfrac{1}{2}(44)(\sqrt{672})  \right]}
\\\\\\
8512~~+~~(44)(\sqrt{672})\qquad \approx\qquad 9652.61036291978

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Step-by-step explanation:

The given parameters are;

The percentage by which damaged items are marked down = 25% to 40%

The percentage markdown offered by the newspaper coupon = 10%

The original marked price of the item = GHC 100

We note that a markdown is the difference between the price an item is placed at for retail sale, and the actual price the item is sold

Given that the item is damaged, to have the lowest price, we apply the largest markdown of 40% as follows;

Price of item marked down due to damage, we remove 40% from the price to get;

The markdown due to damage = 40/100 × GHC 100 = GHC 40

The markdown the coupon holder is to get = 10% of the retail price

Given that the damage is not mentioned in the newspaper, we have;

∴ The markdown the coupon holder is to get = 10/100 × GHC 100 = GHC 10

The total markdown is therefore equal to GHC 40 + GHC 10 = GHC 50

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The lowest price of the item = Original price - Maximum markdown

The lowest price of the item = GHC 100 - GHC 50 = GHC 50

Learn more about markdown here;

brainly.com/question/20705786

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