Question

If I have 3.2 moles of gas at a pressure of 0.095 atm and at a temperature o 43 C what is the volume of the container that the gas is in?

Answer 1

Answer

The volume of the container that the gas is in = 874.30 L

Explanation

Given:

Moles, n = 3.2 mol

Pressure, P = 0.095 atm

Temperature, T = 43 °C = (43 + 273.15 K) = 316.15 K

Molar gas constant, R = 0.0821 atm•L/mol•K

What to find:

The volume of the container that the gas occupied.

Step-by-step solution:

The volume of the container that the gas occupied can be calculated using the ideal gas equation.

$\begin{gathered} PV=nRT \\ \\ \Rightarrow V=\frac{nRT}{P}=\frac{3.2mol\times0.0821atm•L/mol•K\times316.15K}{0.095atm} \\ \\ V=\frac{83.058928\text{ }atm•L}{0.095\text{ }atm}=874.30\text{ }L \end{gathered}$

Therefore, the volume of the container that the gas occupied is 874.30 L