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Ira Lisetskai [31]
1 year ago
8

If I have 3.2 moles of gas at a pressure of 0.095 atm and at a temperature o 43 C what is the volume of the container that the g

as is in?
Chemistry
1 answer:
andriy [413]1 year ago
5 0

Answer

The volume of the container that the gas is in = 874.30 L

Explanation

Given:

Moles, n = 3.2 mol

Pressure, P = 0.095 atm

Temperature, T = 43 °C = (43 + 273.15 K) = 316.15 K

Molar gas constant, R = 0.0821 atm•L/mol•K

What to find:

The volume of the container that the gas occupied.

Step-by-step solution:

The volume of the container that the gas occupied can be calculated using the ideal gas equation.

\begin{gathered} PV=nRT \\  \\ \Rightarrow V=\frac{nRT}{P}=\frac{3.2mol\times0.0821atm•L/mol•K\times316.15K}{0.095atm} \\  \\ V=\frac{83.058928\text{ }atm•L}{0.095\text{ }atm}=874.30\text{ }L \end{gathered}

Therefore, the volume of the container that the gas occupied is 874.30 L

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Estimate the coordination number for the cations in each of these ceramic oxides and also the coordination numbers of the oxygen
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Answer:

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The coordination number CN is the number of ligand atoms bonded (coordinate bonds) directly to the central of the metal ion. It is not the same as the oxidation state of the metal ion or complex.

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In solving for CN we need to understand Pauling's rules.

According to Linus Pauling, 1932

“Pauling’s rules” for crystal structures, makes assumptions for ionic bonding. It states that ionic structure is understood using electrostatic rules of attraction and repulsion.

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Ratio of cationic/anionic radius

• The structure of D-Al2O3 results in coordination number of 6 and 4 for cation and anion respectively.

• The average oxygen coordination number in v-B2O3 is equal to the average cation coordination number × cation/anion ratio (2/3).

• Co-ordination number of Ca2+ ion is =6;

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r⁺/r⁻ = 100 / 145

r⁺/r⁻ = 0.69

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For TiO2:

The CN of the titanium (IV) cation is 6, which is twice the CN of the oxide anion, which is 3.

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