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malfutka [58]
3 years ago
6

An object has a mass of 18.4g and a volume of 11.2 ml what is the density

Chemistry
2 answers:
DENIUS [597]3 years ago
4 0

Density=mass/volume

Density=18.4g/11.2ml

Density=1.64

Just make sure you include the unit of measurement with your answer.

kari74 [83]3 years ago
3 0

Answer:

Density of the object, \rho=1.64\ g/mL

Explanation:

It is given that,

Mass of the object, m = 18.4 g

Volume of the object, V=11.2\ mL

We need to find the density of the object. The density of a material is given by total mass divided by total occupied volume. Its formula is given by :

d=\dfrac{m}{V}

d=\dfrac{18.4\ g}{11.2\ mL}

d=1.64\ g/mL

So, the density of the object is 1.64\ g/mL. Hence, this is the required solution.

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Elis [28]

Answer:

6. In order from left to right the balanced coeficcients are,

6, 1, 2, 3

8. C_{7}H_{10}_{(l)}+6H_{(g)}=C_{7}H_{16}_{(l)

9.  In order from left to right the balanced coeficcients are,

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4 0
2 years ago
What is the pOH of a solution of HNO3 that has [OH-] = 9.50 10-9 M?
bekas [8.4K]

Answer:

The pOH of HNO₃ solution that ha OH⁻ concentration 9.50 ×10⁻⁹M is 8.

Explanation:

Given data:

[OH⁻] = 9.50 ×10⁻⁹M

pOH = ?

Solution:

pOH = -log[OH⁻]

Now we will put the value of OH⁻ concentration.

pOH = -log[9.50 ×10⁻⁹M]

pOH = 8

Thus the pOH of HNO₃ solution that ha OH⁻ concentration 9.50 ×10⁻⁹M is 8.

6 0
3 years ago
Read 2 more answers
A gas sample is collected in a 0.279 L container at 22.7 °C and 0.764 atm. If the sample has a mass of 0.320 g, what is the iden
Sindrei [870]

Answer:

HCl

Explanation:

<em>Choices:</em>

<em>CO: 28.01g/mol</em>

<em>NO₂: 46g/mol</em>

<em>CH₄: 16.04g/mol</em>

<em>HCl: 36.4g/mol</em>

<em>CO₂: 44.01g/mol</em>

<em />

It is possible to identify a substance finding its molar mass (That is, the ratio between its mass in grams and its moles). It is possible to find the moles of the gas using general ideal gas law:

PV = nRT

<em>Where P is pressure of gas 0.764atm; V its volume, 0.279L; n moles; R gas constant: 0.082atmL/molK and T its absolute temperature, 295.85K (22.7°C + 273.15).</em>

Replacing:

PV = nRT

PV / RT = n

0.764atm*0.279L / 0.082atmL/molKₓ295.85K = n

<em>8.786x10⁻³ = moles of the gas</em>

<em />

As the mass of the gas is 0.320g; its molar mass is:

0.320g / 8.786x10⁻³moles = 36.4 g/mol

Based in the group of answer choices, the identity of the gas is:

<h3>HCl</h3>

<em />

4 0
3 years ago
Unstable isotopes undergo radioactive decay. what occurs during radioactive decay?
mel-nik [20]
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5 0
3 years ago
Calculate the volume 3.00 moles of a gas will occupy at 24.0˚C and 1.003 atm. *
vitfil [10]

Answer: 72.93 litres

Explanation:

Given that:

Volume of gas (V) = ?

Temperature (T) = 24.0°C

Convert 24.0°C to Kelvin by adding 273

(24.0°C + 273 = 297K)

Pressure (P) = 1.003 atm

Number of moles (n) = 3 moles

Molar gas constant (R) is a constant with a value of 0.0821 atm L K-1 mol-1

Then, apply ideal gas equation

pV = nRT

1.003 atm x V = 3.00 moles x 0.0821 atm L K-1 mol-1 x 297K

1.003 atm•V = 73.15 atm•L

Divide both sides by 1.003 atm

1.003 atm•V/1.003 atm = 73.15 atm•L/1.003 atm

V = 72.93 L

Thus, the volume of the gas is 72.93 litres

5 0
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