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nignag [31]
11 months ago
9

Which of the following constants can be added to x2 - 3x to form a perfect square trinomail?

Mathematics
1 answer:
serious [3.7K]11 months ago
4 0

The constant that can be added to x^2 - 3x to form a perfect square trinomial is 2\frac{1}{4}

The given expression is

x^2 - 3x

To form a perfect square trinomial

(a-b)^2 =a^2-2ab+b^2

The given expression is

x^2 - 3x

first we have to add a constant term with it

x^2 - 3x + z

By comparing the given expression and the perfect square trinomial

a^2 =x^2

a = x

Similarly

-2ab = 3x

where know a =x

Then,

-2b = 3

b = -3/2

Similarly

b^2 = z

(\frac{-3}{2})^2 = z

9/4 = z

Convert the simple fraction to mixed fraction

9/4 = 2\frac{1}{4}

Hence, the constant that can be added to x^2 - 3x to form a perfect square trinomial is 2\frac{1}{4}

The complete question is :

Which of the following constants can be added to x2 - 3x to form a perfect square trinomial?

1\frac{1}{2},2\frac{1}{4} and 4\frac{1}{2}

Learn more about perfect square trinomial here

brainly.com/question/16615974

#SPJ1

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The number of motor vehicles registered in millions in the US has grown as follows:
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Answer:

a) Figure attached

b) r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}  

For our case we have this:

n=10 \sum x = 75.819, \sum y = 43.5231, \sum xy = 330.0321, \sum x^2 =574.8598, \sum y^2 =192.8274  

r=\frac{10(330.0321)-(75.81948)(43.5231)}{\sqrt{[10(574.8598) -(75.819)^2][10(192.8274) -(43.5231)^2]}}=0.989  

So then the correlation coefficient would be r =0.989

Step-by-step explanation:

Previous concepts

The correlation coefficient is a "statistical measure that calculates the strength of the relationship between the relative movements of two variables". It's denoted by r and its always between -1 and 1.

Solution to the problem

Part a

Year (x): 1940, 1945 1950, 1955, 1960, 1965, 1970, 1975, 1980, 1985

Vehicles (Y): 32.4, 31.0, 49.2, 62.7, 73.9, 90.4, 108.4, 132.9, 155.8, 171.7

After apply natural log for the two variables and create the scatterplot in excel we got the following result on the figure attached.

Part b

And in order to calculate the correlation coefficient we can use this formula:  

r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}  

For our case we have this:

n=10 \sum x = 75.819, \sum y = 43.5231, \sum xy = 330.0321, \sum x^2 =574.8598, \sum y^2 =192.8274  

r=\frac{10(330.0321)-(75.81948)(43.5231)}{\sqrt{[10(574.8598) -(75.81948)^2][10(192.8274) -(43.5231)^2]}}=0.989  

So then the correlation coefficient would be r =0.989

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2 years ago
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