Answer:
![-3y^2 - 8y-12](https://tex.z-dn.net/?f=-3y%5E2%20-%208y-12)
Steps:
Simplify each term.
![-5y^2-9y-4+2y^2+y-8](https://tex.z-dn.net/?f=-5y%5E2-9y-4%2B2y%5E2%2By-8)
Simplify by adding terms.
![-3y^2-8y-12](https://tex.z-dn.net/?f=-3y%5E2-8y-12)
<em>good luck, hope this helps :)</em>
You can use simultaneous linear equations in two variables to solve this word problem.
Let Juwan's age be
![x - years](https://tex.z-dn.net/?f=x%20%20-%20years)
and Christy's age be
![y - years](https://tex.z-dn.net/?f=y%20-%20years)
Let us sum their ages and equate it to 92
![x + y = 92 - - - (1)](https://tex.z-dn.net/?f=x%20%2B%20y%20%3D%2092%20-%20%20-%20%20-%20%281%29)
Ten years ago, Juwan's age was
![(x - 10)years](https://tex.z-dn.net/?f=%28x%20-%2010%29years)
and Christy's age was
![(y - 10)years](https://tex.z-dn.net/?f=%28y%20-%2010%29years)
By then Juwan's age was 3 times Christy's age
![(x - 10) = 3(y - 10)](https://tex.z-dn.net/?f=%28x%20-%2010%29%20%3D%203%28y%20-%2010%29)
Expand and simplify,
![x - 10 = 3y - 30](https://tex.z-dn.net/?f=x%20-%2010%20%3D%203y%20-%2030)
![x = 3y - 20 - - (2)](https://tex.z-dn.net/?f=x%20%3D%203y%20-%2020%20-%20%20-%20%282%29)
Put equation (2) in equation (1)
![3y - 20 + y = 92](https://tex.z-dn.net/?f=3y%20-%2020%20%2B%20y%20%3D%2092)
![4y = 112](https://tex.z-dn.net/?f=4y%20%3D%20112)
![y = 28](https://tex.z-dn.net/?f=y%20%3D%2028)
![x = 3(28) - 20 = 64](https://tex.z-dn.net/?f=x%20%3D%203%2828%29%20-%2020%20%3D%2064)
Juwan is 64 now
80% = 80/100 = 8/10 = 4/5
Answer: 4/5