One of the roots of a quadratic equation is 7 - √3.
Because rational roots occur in conjugate pairs, the other root is 7 + √3.
The quadratic equation is
(x -(7-√3))(x - (7+√3))
= x² - (7+√3)x - (7-√3)x + (49-3)
= x² - 7x - (√3)x - 7x + (√3)x + 46
= x² - 14x + 46
Answer: x² - 14x + 46
So you have to answer all the questions for 4?
Answer:
2x-12+5=3x-3
1. subtract 3x-2x
-12+5=x-3
2.-12 add to 5
-7=x-3
3. add three to seven
-4=x
Step-by-step explanation:
The total number of students is 250 from the solution in the image.
Just add the numbers if the letters are the same only I multiplying do you add the exponents
Answer 14 b^5
