The First is sec^2(x). Second is 2sec^2tanx. From that you get 2[2sec^2xtan^x+sec^4x]
Answer:
6,271
Step-by-step explanation:
For x = 20 days: f(20) = 33(1.3)^20 = 33(190.0496377) = 6,271
To answer this, we need to see the polynomial. Descending order is in a way that the first term of the polynomial will be three, the second (in descending order, two....and so on).
420t+20t3-210t2
In descending order is:
20t^3 - 210t^2 + 420t
So, the option is number two.
Answer:
can you write the whole question in that problem!
