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ICE Princess25 [194]
1 year ago
5

Teri invested $1500 in an account with an interest rate of 2.25% compounded continuously. How long will it take for Teri's accou

nt to earn $5000?
Mathematics
1 answer:
tester [92]1 year ago
7 0

It will take 54 days for Teri's account to earn an amount of $5000.

<h3>What is compound interest?</h3>

Compound interest, also known as interest on principal and interest, is the practice of adding interest to the principal amount of a loan or deposit.

It occurs when interest is reinvested, or added to the loaned capital rather than paid out, or when the borrower is required to pay it, so that interest is generated the next period on the principal amount plus any accumulated interest. In finance and economics, compound interest is common.

It is given by formula

A = p*e^{r*t}

where:

A is final amount

p is principal amount

r is rate of interest and

t, is time period

Given: A= $5000, p=$1500, r=2.25% = 0.0225

To find: time period to get compounded amount

5000=1500×e^{0.0225*t}

e^{0.0225t} = \frac{10}{3}

0.0225t = ㏑ (\frac{10}{3})

t = 53.5099 ≈ 54 days  

Learn more about compound interest here:

brainly.com/question/3989769

#SPJ1

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the price p of a clubs membership is $30 foran enrollment fee and $12 per week w tobe a member .Write a function
Georgia [21]

The function would be

p = $30 + $12w

or

p = $12w + 30

4 0
3 years ago
You have just been paid for mowing nine lawns, and you earned $7 per lawn. If you were paid $9 per lawn, how many lawns would yo
forsale [732]

Answer:

if you got paid seven bucks per lawn, and you mowed nine lawns, you'd have $63 dollars

if you were to mow them for 9 dollars a lawn...

$63 = 9x

63/9 = 7

youd have to mow 7 lawns to get the same amount of money

Step-by-step explanation:

7 0
2 years ago
Student to faculty is 17:3 The total is 740 how many students and faculty are at the college
inn [45]
Let the faculties be X and the number of students be Y.
X/Y = 17/3
3X= 17Y
X=17Y/3
Let that be equation 1
We also know that X+Y = 740. Let it be equation 2
Substitute equation 1 in equation 2
(17Y/3)+Y=  740
20Y/3 = 740
Y=111
Since the total is 740, then X equal 740-111 =629.
The number of faculties is 111 and the number of students is 629.
7 0
3 years ago
Read 2 more answers
a. Fill in the midpoint of each class in the column provided. b. Enter the midpoints in L1 and the frequencies in L2, and use 1-
Tresset [83]

Answer:

\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1}  & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7}  & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}

Using the frequency distribution, I found the mean height to be 70.2903 with a standard deviation of 3.5795

Step-by-step explanation:

Given

See attachment for class

Solving (a): Fill the midpoint of each class.

Midpoint (M) is calculated as:

M = \frac{1}{2}(Lower + Upper)

Where

Lower \to Lower class interval

Upper \to Upper class interval

So, we have:

Class 63-65:

M = \frac{1}{2}(63 + 65) = 64

Class 66 - 68:

M = \frac{1}{2}(66 + 68) = 67

When the computation is completed, the frequency distribution will be:

\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1}  & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7}  & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}

Solving (b): Mean and standard deviation using 1-VarStats

Using 1-VarStats, the solution is:

\bar x = 70.2903

\sigma = 3.5795

<em>See attachment for result of 1-VarStats</em>

8 0
3 years ago
PLSS HELP
dsp73

Answer:

B,C, and D

Give thanks and brainliest!! :P

4 0
3 years ago
Read 2 more answers
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