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RoseWind [281]
3 years ago
7

Find the midpoint of (-4,-2) and (4,-2)

Mathematics
2 answers:
xeze [42]3 years ago
4 0

\huge\text{Hey there!}

\large\textsf{Your formula is:}\downarrow

\mathsf{M = (\dfrac{x_1+x_2}{2}, \dfrac{y_1+y_2}{2})}

\mathsf{x_1 = -4}

\mathsf{x_2 = 4}

\mathsf{y_1 = -2}

\mathsf{y_2 = -2}

\mathsf{Equation: m= (\dfrac{-4+4}{2}, \dfrac{-2+-2}{2})}

\mathsf{-4 + 4 = \bf 0}

\mathsf{m = (\dfrac{0}{2},\dfrac{-2+-2}{2})}

\mathsf{-2 + -2 = \bf -4}

\mathsf{m = (\dfrac{0}{2}, \dfrac{-4}{2})}

\mathsf{\dfrac{0}{2}=\bf 0}

\mathsf{\dfrac{-4}{2}=\bf -2}

\mathsf{m= \bf (0, -2)}

\boxed{\boxed{\large\text{Answer: \huge \bf (0,-2)}}}\huge\checkmark

\text{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}

yKpoI14uk [10]3 years ago
3 0

Answer:

(0,−2)

Step-by-step explanation:

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so therefor
perimiter=sides added up
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s+7 and 3s
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