If x=1 and y=2, what is the value of the expression 2x^2-3xy

Jillian is making accessories for the soccer team. She uses 761.78 inches of fabric on headbands for 39 players and 2 coaches. S

Tema [17]

Answer:

Head bands: 18.58 inches of fabric

Wrist bands : 8.51 inches of fabric

Step-by-step explanation:

Jillian is making accessories for the soccer team.

For head bands

She uses 761.78 inches of fabric on headbands for 39 players and 2 coaches.

The total number of people = 39 player + 2 coaches = 41 people

Hence:

41 persons = 761.78 inches of fabric

1 person = x

Cross Multiply

41 × x = 761.78 × 1

x = 761.78/48

x = 18.58 inches

For wristbands

She also uses 331.89 inches of fabric on wristbands for just the players.

Number of players = 39 players

Hence:

39 players = 331.89 inches

1 players = x inches

Cross Multiply

39 × x = 1 × 331.89 inches

x = 331.89 inches/39

x = 8.51 inches

Therefore:

18.58 inches of fabric was used for head bands and 8.51 inches of fabrics was used for wristbands.

5 0

3 years ago

You deposit $2000 each year into an account earning 3% interest compounded annually. How much will you have in the account in 25

kozerog [31]

This is what I get. Total will be 4187.56 with Interest 2187.56. By using the formula: To find amount : A=p (1+r/n)^n×t Where P=2000,r=3%,n=1,t=25 So plug in and solve A=2000(1+0.03/1)^1×25 To find interest you use formula A=p+I A=4187.56, p=2000,i= we need to find. 4187.56=2000+I 4187.56-2000=I 2187.56=i

3 0

3 years ago

You are purchasing a car for $12,465.00 plus 5.65% sales tax. You make a $1,300.00 down payment and have a fair credit score. If

pochemuha

Answer:

21.74

Step-by-step explanation:

4 0

3 years ago

Find the derivative.

krek1111 [17]

Answer:

$\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}$

General Formulas and Concepts:

Algebra I

Terms/Coefficients

Expanding/Factoring

Calculus

Differentiation

Derivatives
Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Quotient Rule]: $\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle f(x) = \frac{\sqrt{x}}{e^x}$

Step 2: Differentiate

Derivative Rule [Quotient Rule]: $\displaystyle f'(x) = \frac{(\sqrt{x})'e^x - \sqrt{x}(e^x)'}{(e^x)^2}$
Basic Power Rule: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}(e^x)'}{(e^x)^2}$
Exponential Differentiation: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{(e^x)^2}$
Simplify: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{e^{2x}}$
Rewrite: $\displaystyle f'(x) = \bigg( \frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x \bigg) e^{-2x}$
Factor: $\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}$