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ivann1987 [24]
1 year ago
12

Solve. Find all solutions in [0,2).5 secx cotx+5 secx+ cotx+1=0

Mathematics
1 answer:
Dmitrij [34]1 year ago
5 0
\begin{gathered} 5sec(x)cot(x)+5sec(x)+cot(x)+1=0 \\ Factoring \\ (cot(x)+1)(5sec(x)+1)=0 \\ cot(x)+1=0 \\ cot(x)=-1 \\ x=cot^{-1}(1) \\ x=\frac{3\pi}{4} \\  \\ 5sec(x)+1=0 \\ 5sec(x)=-1 \\ sec(x)=\frac{-1}{5},\text{ there is no solution} \\ Hence \\ All\text{ solution are }\frac{3\pi}{4}+\pi n,\text{ where n=1,2,3...} \\  \\  \end{gathered}

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Please, do not post more than 1 or 2 questions at a time.  Out of courtesy I will address one of your six questions here:

<span>2x + 4 = 3(x – 2) + 1

You are to solve this for x.

1) perform the multiplication:     </span><span>2x + 4 = 3x - 6 + 1
2) combine like terms:                4+6-1 = x
3) solve for x:                              x = 11
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Check:  Is 2(9) + 4 = 3(9-2) + 1 true?  Is 18+4 = 22 true?  YES.
The solution to #1 is  x = 9  (answer).

Submit your other questions separately, please.

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