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spayn [35]
3 years ago
7

An experiment is performed where a card is chosen from a desk of playing cards

Mathematics
1 answer:
Anna71 [15]3 years ago
5 0
Ok
I need the question for this
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-3|6-2x|+2=-10 <br> Solve absolute value- help pls!
yaroslaw [1]
X=1,5

I think yeah it should be that
8 0
3 years ago
(3^5 x 3^7) = 3^35 is this true
ella [17]

Answer:

False

Step-by-step explanation:

you have to solve the problems inside the parentheses first so you would have to multiply everything inside so no ur wrong

Real answer is: 531,441

3 0
3 years ago
A square with a side length of x+6 has the same perimeter as an equilateral triangle with a side length of 4 x what is the area
prohojiy [21]
The perimeter of the equilateral triangle is 3s and s=4x so the perimeter is:

12x

And we are told that the perimeter of the square is the same.  And that perimeter is 4s where s=(x+6) so that perimeter is equal to

4x+24, and again, we are told that these two values are equal so we can solve for x...

12x=4x+24

8x=24

x=3 and if x=3 then the side length is (x+6)=9

So the area of the square is always A=s^2 and s=9 thus:

A=9^2

A=81 u^2
7 0
3 years ago
Can someone please help me! I don’t understand how to do this!
Nutka1998 [239]

9514 1404 393

Answer:

  a.  4x^2 +16x -48 = 4x^2 +16x -48

  b.  -3x^2 +12x +36 = -3x^2 +12x +36

  c.  x^2 +12x +35 = x^2 +12x +35

Step-by-step explanation:

In general, you would prove this by transforming one of the expressions into the other. The easiest would be to transform the factored form into the vertex form, perhaps, as this would spare you trying to explain the magic of factoring.

Alternatively, you can transform both expressions into the same (standard) form. I believe that will be the easiest of all.

The product of two binomials is ...

  (x +a)(x +b) = x(x +b) +a(x +b) = x^2 +bx +ax +ab

  (x +a)(x +b) = x^2 +(a+b)x +ab . . . . after collecting terms

The square of a binomial is the same thing, but with b=a, so ...

  (x +a)^2 = x^2 +2a +a^2

Using these forms, we can avoid showing all of the intermediate "work" of making the desired transformations.

__

a.  4(x -2)(x +6) = 4(x +2)^2 -64

  4(x^2 +4x -12) = 4(x^2 +4x +4) -64 . . . . . expanding the products

  4x^2 +16x -48 = 4x^2 +16x +16 -64 . . . . using the distributive property

  4x^2 +16x -48 = 4x^2 +16x -48 . . . . . collect terms; expressions are equal

__

b.  -3(x +2)(x -6) = -3(x -2)^2 +48

  -3(x^2 -4x -12) = -3(x^2 -4x +4) +48

  -3x^2 +12x +36 = -3x^2 +12x -12 +48

  -3x^2 +12x +36 = -3x^2 +12x +36

__

c.  (x +5)(x +7) = (x +6)^2 -1

  x^2 +12x +35 = x^2 +12x +36 -1

  x^2 +12x +35 = x^2 +12x +35

6 0
3 years ago
Read 2 more answers
PLEASE HELP ME THIS IS FOR A TEST GRADE !!!!! AND I NEED HELP ASAP
kicyunya [14]

g(t) = t - 2\\h(t) = 3t + 3\\(g \circ h)(t) = g(h(t)) = (3t + 3) - 2 = 3t + 3 - 2 = 3t + 1

6 0
3 years ago
Read 2 more answers
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