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Alex17521 [72]
3 years ago
12

Find the measure of arc BEF.

Mathematics
1 answer:
Cerrena [4.2K]3 years ago
6 0

Given:

The diagram of a circle.

m\angle BPV=124^\circ ,m\angle VPE=30^\circ ,m\angle EPF=76^\circ, m\angle FPD=48^\circ.

To find:

The measure of arc BEF.

Solution:

The measure of central angle is equal to the measure of corresponding arc.

So, in the given figure,

n(arcBV)=124^\circ ,m(arcVE)=30^\circ ,m(arcEF)=76^\circ, m(arcFD)=48^\circ

Now,

m(arcBEF)=m(arcBV)+m(arcVE)+m(arcEF)

m(arcBEF)=124^\circ +30^\circ+76^\circ

m(arcBEF)=230^\circ

Therefore, the measure of arc BEF is 230 degrees.

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4 0
3 years ago
A company sells fruit cups in packs of 4. The packs currently weigh 20 oz. The company plans to reduce the weight of each cup by
skad [1K]

Answer:

4 ( 5 - n )

Step-by-step explanation:

The expression:

20 – 4n

Task:  Rewrite the expression for the new weight as a product of two factors.

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Expressing as a product of two factors;

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6 0
3 years ago
Solve x 2 + 9x + 8 = 0 by completing the square. What are the solutions?
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So firstly, what two terms have a product of 8x^2 and a sum of 9x? That would be x and 8x. Replace 9x with x + 8x: x^2+x+8x+8=0

Next, factor x^2 + x and 8x + 8 separately. Make sure that they have the same quantity on the inside: x(x+1)+8(x+1)=0

Now you can rewrite the equation as (x+8)(x+1)=0

Now using zero product property, solve for x:

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<u>In short, the solutions are {-1,-8}, or C.</u>

4 0
4 years ago
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