Answer:
proof below
Step-by-step explanation:
Remember that a number is even if it is expressed so n = 2k. It is odd if it is in the form 2k + 1 (k is just an integer)
Let's say we have to odd numbers, 2a + 1, and 2b + 1. We are after the sum of their squares, so we have (2a + 1)^2 + (2b + 1)^2. Now let's expand this;
(2a + 1)^2 + (2b + 1)^2 = 4a^2 + 4a + 4b + 4b^2 + 4b + 2
= 2(2a^2 + 2a + 2b^2 + 2b + 1)
Now the sum in the parenthesis, 2a^2 + 2a + 2b^2 + 2b + 1, is just another integer, which we can pose as k. Remember that 2 times any random integer, either odd or even, is always even. Therefore the sum of the squares of any two odd numbers is always even.
Answer:
Divide StartFraction a Over 11 EndFraction by 11; the solution is 540.
Step-by-step explanation:
Answer:
The answer is Convex Hexagon I took the quiz
Step-by-step explanation:
If you have to compare two shapes you basically count the number of shapes there are of each type then you say for example 6:4. If they ask you to give the number of shapes to the number of shapes there are you count all the shapes and then you count the shape they asked you to find and then you will get something like 4:15
Answer: I am going to put a link
maybe its going to help you?
Step-by-step explanation:
http://s3.amazonaws.com/illustrativemathematics/illustration_pdfs/000/001/217/original/illustrative_mathematics_1217.pdf?1390751150
