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2 years ago

7

Which of the following can be used to find the sum of the interior angles for any regular polygon?

2 answers:

TiliK225 [7]2 years ago

8 0

<span>Sum of Interior Angles = (Number of Sides -2) • 180 degrees
It seems C is the answer.

</span>

babunello [35]2 years ago

3 0

To find the sum of the interior angles for any regular polygon, you need to subtract 2 from the number of sides and multiply the difference by 180.

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All numbers between 1 and 2 are rational numbers true or false

Novosadov [1.4K]

Given that

1:2

now,

1*2

2

6 0

2 years ago

The table shows a gym class's average results for boys and

Rufina [12.5K]

Susan can jump at most 104 in during the long jump

<h3>Inequality</h3>

Inequality is an expression that show the non equal comparison of two or more variables and numbers.

From the table, the average result for females = 8ft 4in = (8 * 12)in + 4in = 100 in

Since Susan could jump no farther than 4 inches more than the average distance for females, hence:

j ≤ 4 + 100

j ≤ 104 in

Susan can jump at most 104 in during the long jump

Find out more o Inequality at: brainly.com/question/24372553

5 0

1 year ago

Suppose you like to keep a jar of change on your desk. Currently, the jar contains the following: 22 Pennies 27 Dimes 9 Nickels

kap26 [50]

Answer:

$P(Penny\ and\ Dime) = \frac{9}{116}$

Step-by-step explanation:

Given

$Pennies = 22$

$Dimes = 27$

$Nickels = 9$

$Quarters = 30$

Required

$P(Penny\ and\ Dime)$

This is calculated as:

$P(Penny\ and\ Dime) = P(Penny) * P(Dime)$

Since it is a selection without replacement, the computation is:

$P(Penny\ and\ Dime) = \frac{Penny}{Total} * \frac{Dime}{Total-1}$

So, we have:

$P(Penny\ and\ Dime) = \frac{22}{22+27+9+30} * \frac{Dime}{22+27+9+30-1}$

$P(Penny\ and\ Dime) = \frac{22}{88} * \frac{27}{87}$

$P(Penny\ and\ Dime) = \frac{1}{4} * \frac{9}{29}$

$P(Penny\ and\ Dime) = \frac{9}{116}$

5 0

2 years ago

Write the equation for the hyperbola with foci (–12, 6), (6, 6) and vertices (–10, 6), (4, 6).

fomenos

Answer:

$\frac{(x--3)^2}{49} -\frac{(y-6)^2}{32}=1$

Step-by-step explanation:

The standard equation of a horizontal hyperbola with center (h,k) is

$\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1$

The given hyperbola has vertices at (–10, 6) and (4, 6).

The length of its major axis is $2a=|4--10|$ .

$\implies 2a=|14|$

$\implies 2a=14$

$\implies a=7$

The center is the midpoint of the vertices (–10, 6) and (4, 6).

The center is $(\frac{-10+4}{2},\frac{6+6}{2}=(-3,6)$

We need to use the relation $a^2+b^2=c^2$ to find $b^2$ .

The c-value is the distance from the center (-3,6) to one of the foci (6,6)

$c=|6--3|=9$

$\implies 7^2+b^2=9^2$

$\implies b^2=9^2-7^2$

$\implies b^2=81-49$

$\implies b^2=32$

We substitute these values into the standard equation of the hyperbola to obtain:

$\frac{(x--3)^2}{7^2} - \frac{(y-6)^2}{32}=1$

$\frac{(x+3)^2}{49} -\frac{(y-6)^2}{32}=1$

7 0

2 years ago

Sammy drew a rectangle that was w inches wide. The length was 4 inches more than the width. Which expression below represents th

LekaFEV [45]

4w +8. C.

It’s 4 * width for perimeter and two of the sides are longer by 4in so 2*4=8

7 0

2 years ago