<span>A. Acquired traits can be passed to offspring
Jean-Baptiste Lamarck first presented his Theory of Inheritance of Acquired Characteristics in 1801. According to his theory, if an organism changes in order to adapt to its environment, the changes are passed on the organism's offspring. Some of his proposed ideas in the theory, however, were dismissed by other scientists by experimenting and studying of genetics.</span>
Answer:
1. Double helix is the description of the structure of a DNA molecule. A DNA molecule consists of two strands that wind around each other like a twisted ladder. Each strand has a backbone made of alternating groups of sugar (deoxyribose) and phosphate groups.
2. The DNA double helix. The two sides are the sugar-phosphate backbones, composed of alternating phosphate groups and deoxyribose sugars. The nitrogenous bases face the center of the double helix.
3. A nucleotide is an organic molecule that is the building block of DNA and RNA. ... A nucleotide is made up of three parts: a phosphate group, a 5-carbon sugar, and a nitrogenous base. The four nitrogenous bases in DNA are adenine, cytosine, guanine, and thymine.
4. A nucleotide is made up of three parts: a phosphate group, a 5-carbon sugar, and a nitrogenous base. The four nitrogenous bases in DNA are adenine, cytosine, guanine, and thymine.
5. In genetics, the term junk DNA refers to regions of DNA that are non-coding. Some of this noncoding DNA is used to produce noncoding RNA components such as transfer RNA, regulatory RNA and ribosomal RNA
Hopes this helps.
Answer:
0.8
Explanation:
There is a population where the frequencies of allele 1 and allele 2 are 0.7 and 0.3, respectively
Let's use GG to represent allele 1
Let's use gg to represent allele 2
So we can equally say that;
GG = p = 0.7
gg = q = 0.3 ( from Hardy-Weinberg Equilibrium)
So, given that the selection coefficient = 0.2
We known that the cross between GG and gg will definitely results to (GG,Gg and gg)
Then the fitness of these genes can be represented as:
1 - s, 1 and 1 - t respectively.
Thus. the allele 1's genotype fitness can be determined as
= 1 - s ( where s is the selection coefficient)
= 1 - 0.2
= 0.8
