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maria [59]
1 year ago
15

Which of the following problem types can always be solved using the law of cosines or sines? Check all that apply.A. SSSB. AAAC.

ASAD. SAAE. SSAF. SAS
Mathematics
1 answer:
Sphinxa [80]1 year ago
8 0

The law of sines can be solved for the following cases:

• AAS

,

• ASA

,

• SSA (But this can be ambigous)

The law of cosines can be solved for the following cases:

• SAS

,

• SSS

Thererefore, the correct options are A, C, E, D and F

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Margaret is planning a wedding reception. She wants to spend less than her budget of $5,748, and Margaret has already spent $2,4
noname [10]

Answer:

She can invite 109 guests and be right on top of budget. If she wants to spend less than her budget though she can only invite 108 people.

Step-by-step explanation:

First you have to subtract 5,748 - 2,478 which is 3270. Next you have to divide 3270 by 30 because each person costs 30 dollars. 3270 divided by 30 is 109.

I hope this helps! Please mark me brainliest if I am correct! Have a nice day!

6 0
3 years ago
Cal is measuring temperature changes in four substances over different time periods as part of a school project. Which data show
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Answer:

C) The third table. K= 5

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Step-by-step explanation:

1) Below there are the missing data:

A proportional relationship through a constant k. It is obtained when we divide:

k=\frac{y}{x}

2)In this case, when we divide the temperature (T) by the time (h).

k=\frac{T}{h}

3)So, examining the table below we are searching for a ratio k common to all measures (temperatures over hour).

A) \frac{12}{3}\neq\frac{25}{5}\neq\frac{36}{6}\neq\frac{81}{9}\\B) \frac{22.5}{3}\neq\frac{30}{4}\neq\frac{52.5}{7}\neq\frac{67.5}{8}\\C)\frac{10}{2}=\frac{15}{3}=\frac{25}{5}=\frac{40}{8}=k= 5\\D)\frac{8.5}{2}\neq\frac{22.5}{5}\neq\frac{28.5}{7}\neq\frac{36}{8}

3 0
3 years ago
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Answer:

=6-i+4+2i+2-i

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3 years ago
2n +5)=2<br> Help me please
Kobotan [32]

Answer:

-1.5

Step-by-step explanation:

8 0
3 years ago
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