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Alchen [17]
3 years ago
15

Find the midpoint between the points (7, -2) and (-4, 2). Write your answer in the proper form using parentheses

Mathematics
1 answer:
Elan Coil [88]3 years ago
3 0

Answer:

( 1.5, 0)

Step-by-step explanation:

1. Find the coordinates ; in this case (7,-2) and (-4, 2)

2. Plug it into the formula (x1 + x2 ÷ 2 ) , (y1 + y2 ÷ 2)

3. ( 7 +  -4 ÷2) = 1.5    And    ( -2 + 2 ÷ 2) = 0

4. Therefore, the midpoint is ( 1.5, 0 )

                                         

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Please help me with this
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Answer:

  • 8 3/4
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Step-by-step explanation:

<h3>a)</h3>

The first line is simply the sum of the two given numbers.

  3 1/2 +5 1/4 = (3+5) +(2/4+1/4) = 8 3/4

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To find values on the remaining lines, it is convenient to find the ratios of the numbers involved. The ratio of yellow to blue is ...

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Then ...

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This tells you the numbers on the second line are ...

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The value for B on the third line is the basic ratio number multiplied by (6 3/4)/3 = 2 1/4. Then the other two numbers are ...

  Y = 2(2 1/4) = 4 1/2

  total = 5(2 1/4) = 11 1/4

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The value for Y on the fourth line is the basic ratio number multiplied by (6 1/2)/2 = 3 1/4. Then the other two numbers are ...

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_____

<h3>b)</h3>

The equation is the one we used to find the values on the second line:

  Y/B = 2/3

7 0
2 years ago
The diameter of a circle is 50 inches.The radius of the circle is A) 100 inches B) 25 inches C) 157 inches D) 45 inches ...so wh
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I've been trying to get an answer for this all day and don't know where to begin what is the answer like I have no clue ​
Shtirlitz [24]

so, we have two 54x18 rectangles, so their perimeter is simply all those units added together, 54+54+54+54+18+18+18+18 = 288.

we know the circle's diameter is 1.5 times the width, well, the width is 18, so the diameter of the circle must be 1.5*18 = 27.

\bf \stackrel{\textit{circumference of a circle}}{C=d\pi }~~ \begin{cases} d=diameter\\[-0.5em] \hrulefill\\ d=27 \end{cases}\implies C=27\pi \implies C=\stackrel{\pi =3.14}{84.78} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{perimeter of the rectangles}}{288}~~~~+~~~~\stackrel{\textit{perimeter of the circle}}{84.78}~~~~=~~~~372.78

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3 years ago
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