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Stella [2.4K]
3 years ago
7

You have in the class 11 boys and 8 girls. You also have 3 seniors, 4 juniors, and 12 sophomores. If you select a student at ran

dom, what is the probability you select a boy *
1 point
11/38
7/11
11/19
19/11
Mathematics
1 answer:
Daniel [21]3 years ago
5 0

Answer:

38

Step-by-step explanation:

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Urgent!!! PLEASE HELP, FAST!!!
gayaneshka [121]
The best way to solve this is to put it into a proportion:
\frac{x}{84} = \frac{ \frac{1}{4} }{ \frac{3}{4} }
So you cross multiply to get:
21= \frac{3}{4} x (the 21 is from \frac{1}{4}•84)
Then multiply by \frac{4}{3}
And you get $28, so the reduced price would be $28.
6 0
3 years ago
Help as soon as possible!
8090 [49]

Step-by-step explanation:

Since both terms are perfect squares, factor using the difference of squares formula, a 2 − b 2 = ( a + b ) ( a − b ) where a = 7 and b = a + x . − ( 7 + a + x ) ( a + x − 7 )

7 0
2 years ago
What is the value of x in the equation (5^x)^5=5^35
Arada [10]

\bf (5^x)^5=5^{35}\implies 5^{x\cdot 5}=5^{35}\impliedby \begin{array}{llll} \textit{same bases}\\ \textit{same exponents} \end{array}\implies 5x = 35 \\\\\\ x = \cfrac{35}{5}\implies x=7

6 0
3 years ago
the ratios of girls to boys in a student basketball league is 5:6. juan says that there must be exactly 11 students in the leagu
Alex787 [66]

Answer:

False

Step-by-step explanation:

girls : boys : total

5       : 6      :11

Multiply each term by 2

10:      12     :22

Ratio of girls to boys

10:12

Divide by 2

5:6

The ratio of girls to boys is still 5:6  but the total students is 22

8 0
3 years ago
Read 2 more answers
Help! Thanks!!!!!!!!!
san4es73 [151]

1)

∠BAC = ∠NAC - ∠NAB = 144 - 68 = 76⁰

AB = 370 m

AC = 510 m

To find BC we can use cosine law.

a² = b² + c² -2bc*cos A

|BC|² = |AC|²+|AB|² - 2|AC|*|AB|*cos(∠BAC)

|BC|² = 510²+370² - 2*510*370*cos(∠76⁰) =

|BC| ≈ 553 m


2)

To find ∠ACB, we are going to use law of sine.

sin(∠BAC)/|BC| = sin(∠ACB)/|AB|

sin(76⁰)/553 m = sin(∠ACB)/370 m

sin(∠ACB)=(370*sin(76⁰))/553 =0.6492

∠ACB = 40.48⁰≈ 40⁰


3)

∠BAC = 76⁰

∠ACB = 40⁰

∠CBA = 180-(76+40) = 64⁰


Bearing C from B =360⁰- 64⁰-(180-68) = 184⁰


4)

Shortest distance from A to BC is height (h) from A to BC.


We know that area of the triangle

A= (1/2)|AB|*|AC|* sin(∠BAC) =(1/2)*370*510*sin(76⁰).

Also, area the same triangle

A= (1/2)|BC|*h = (1/2)*553*h.


So, we can write

(1/2)*370*510*sin(76⁰) =(1/2)*553*h

370*510*sin(76⁰) =553*h

h= 370*510*sin(76⁰) / 553= 331 m

h=331 m


4 0
3 years ago
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