Answer:
m ∠JPN = 131°
Step-by-step explanation:
m ∠JPL = m ∠MPK Vertical angles are =
7x + 19 = 11x -17 Substitution
- 4x = -36 Algebra: Solving for x
x = 9 Algebra: Solving for x
m ∠JPL = 82° Substitution x = 9 into m ∠JPL = 7x +19
m ∠JPL + m ∠LPK = 180° Definition of linear pair/supplement
angles = 180°
82° + m ∠LPK = 180° Substitution
m ∠LPK = 98° Algebra
m ∠LPK = m ∠LPN + m ∠NPK Angle addition Theorem
PN bisects ∠LPK Given
m ∠LPN = m ∠NPK Definition of angle bisector
98 ° = 2 ( m ∠LPN) Substitution
m ∠LPN = 49° Algebra
m ∠JPN = m ∠JPL + m ∠LPN Angle Addition
m ∠JPN = 82° + 49° Substitution
m ∠JPN = 131° Addition
It would be 4/34 or 2/17.
I’m not sure completely if I’m being honest but I get points
Y = mx + b
slope(m) = -1/2
(5,2)...x = 5 and y = 2
sub and find b
2 = -1/2(5) + b
2 = -5/2 + b
2 + 5/2 = b
4/2 + 5/2 = b
9/2 = b
so ur equation for this line is : y = -1/2x + 9/2
y = -1/2x + 9/2......(7,r)....when x = 7
y = -1/2(7) + 9/2
y = -7/2 + 9/2
y = 2/2
y = 1
so ur missing variable is 1......ur set of points would then be (7,1) <=
Answer:
The answer to your question is the letter C
Step-by-step explanation:
To answer this question just look at the graph, the solution to the system of the quadratic equation and the linear function, are the points where these function cross.
The first point where these functions cross is Point C
The second point where these functions cross is Point E
