3 years ago

What are four consecutive odd integers with the sum of 232

1 answer:

7 0

Four consecutive odd integers, eh? Let x be the first of these odd integers. The next odd integer is thus x+2, and the next is x+4, and the last is x+6. The sum of all four of these is 232, so you have x+x+2+x+4+x+6=2324x+12=232

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