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Anon25 [30]
2 years ago
12

Please help me answer this worksheet (Geometry Worksheet 3.3)

Mathematics
1 answer:
AysviL [449]2 years ago
4 0

As per the reference document attached thereby along with the question statement, if (∠SOX = 160°), [∠1 = (x + 14)], and [∠2 = (3x – 10)], then the measure of ∠2 in degrees will be 113°

As per the reference document attached thereby along with the question statement, (∠SOX = 160°), and it's constituent angles

[∠1 = ∠SOW = (x + 14)], and [∠2 = ∠WOX = (3x – 10)],

And we are required to determine the measure of ∠2.

Since, [(∠SOW + ∠WOX) = ∠SOX],

Therefore, [{(x + 14) + (3x – 10)} = 160°]

Or, [{(x + 3x) + (14 - 10)} = 160°]

Or, [(4x - 4) = 160°]

Or, [4x = (160 + 4)°]

Or, (4x = 164°)

Or, [x = (164/4)°]

Or, (x = 41°)

Or, [(3x – 10) = {(3 * 41) - 10}°]

Or, [∠2 = (123 - 10)°]

Or, (∠2 = 113°)

That is, if (∠SOX = 160°), and it's constituent angles (∠1) and (∠2) measure as [∠1 = ∠SOW = (x + 14)], and [∠2 = ∠WOX = (3x – 10)], then the measure of ∠2 in degrees will be 113°

To learn more about Measures in Degrees, click on the link below.

brainly.com/question/12362603

#SPJ1

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Answer:  y = 7cos(0.4π x) - 3

<u>Step-by-step explanation:</u>

The equation of a cosine function is:    y = A cos(Bx - C) + D    where

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(-1.25, -3) is given as a point on the midline.  We only need the y-value.

<u>Horizontal stretch (B) = 0.4π</u>

The max is located at (0,4) and also at (5, 4).  Thus the period (length of one wave) is 5 units.

P=\dfrac{2\pi}{B}\qquad \rightarrow \qquad 5=\dfrac{2\pi}{B}\qquad \rightarrow \qquad B=\dfrac{2}{5}\pi          →     B = 0.4π

<u>Phase Shift (C) = 0</u>

The max is on the y-axis so there is no horizontal shift.

<u>Amplitude (A) = 7</u>

The distance from the midline to the max is: A = 4 - (-3) = 7

<u>Equation</u>

Input A = 7, B = 0.4π, C = 0, and D = -3 into the cosine equation.

            y = A cos(Bx - C) + D

            y = 7cos(0.4π x - 0) - 3

            y = 7cos(0.4π x) - 3

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