3 years ago

Find the 8th term for the sequence a(n)=6-1n

1 answer:

8 0

Answer:

-2

Step-by-step explanation:

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Zielflug [23.3K]

The common ratio between terms is 3, so the sequence has general $n$ -th term

$a_n=3^{n-1}$

for $n\ge1$ . The term exceeds 7000 when

$3^{n-1}>7000\implies n-1>\log_37000\implies n>1+\log_37000\approx9.06$

which means the first time $a_n$ exceeds 7000 occurs when $n=10$ . Indeed,

$a_{10}=3^{10-1}=19,683$

while the previous term would have been

$a_9=3^{9-1}=6561$

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NNADVOKAT [17]

The equation in point slope is: y-y1=m(x-x1) y-6=5(x-2)

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sammy [17]

Answer:

4,-1,-9

Step-by-step explanation:

If you set the factorise to equal zero you can solve for the answer

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Sever21 [200]

Answer:

can't see that

Step-by-step explanation:

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Whitepunk [10]

I would say that the price would be 176.97.

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