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Oksanka [162]
3 years ago
14

The length of PQ is The midpoint of PQ is m(_,_)

Mathematics
1 answer:
nordsb [41]3 years ago
7 0
What first of all this is a test second how are we supposed to do that where can we find M
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Which congruence theorem can be used to prove △ABC ≅ △DBC?
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Answer:

SAS

Step-by-step explanation:

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What is the volume of the pyramid below?
igomit [66]

Answer:

12

Step-by-step explanation:

Base area = 3×4/2 = 6 ft²

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3 years ago
A student wants to estimate the mean score of all college students for a particular exam. First use the range rule of thumb to m
Wewaii [24]

Answer:

See explanation below

<u>Step-by-step explanation:</u>

range = 2200 - 300 = 1900

To find standard deviation, we have:

standard deviation = range/4 = \frac{1900}{4} = 475

The range rule of thumb estimate for the standard deviation is 475

Given:

Standard deviation,\sigma = 475

Margin of Error, ME = 100

\alpha = 1 - 0.90 = 0.10

Za/2 = Z0.05 = 1.64

Find sample size, n:

n ≥ [Z_\alpha_/_2 * (\frac{\sigma}{ME})]^2

n ≥ [1.64 * (\frac{475}{100})]^2

n ≥ 60.68

≈ 61

Minimun sample size,n = 61

5 0
3 years ago
Zalmon walks three fourhs of a mile in three tenths of an hour. what is his speed in miles per hour?
nataly862011 [7]
2.5 miles per hour
Because 3/4 divided by 3/10 is equal to 2.5
4 0
3 years ago
Read 2 more answers
In a church wing with 8 men and 10 women members find the probability that a 5 member committee chosen randomly will have.......
Sergeeva-Olga [200]

Answer:

a) Probability that a 5 member committee will have all men = 0.0065

b) probability that a 5 member committee chosen randomly will have 3 men and 2 women = 0.294

Step-by-step explanation:

Number of men = 8

Number of women = 10

Total number of members = 10 + 8 = 18

Probability = (Number of possible outcomes)/(Total number of outcomes)

Number of ways of selecting a 5 member committee from 18 people = ^{18}C_5 = \frac{18!}{(18-5)!5!} = \frac{18!}{13!5!} = 8568 ways

a) Probability that a 5 member committee will have all men

Number of ways of selecting 5 men from 8 men

= ^8C_5 = \frac{8!}{(8-5)!5!} = \frac{8!}{3!5!} = 56 ways

Probability that a 5 member committee will have all men = 56/8568

Probability that a 5 member committee will have all men = 0.0065

b)probability that a 5 member committee chosen randomly will have 3men and 2 women​

Number of ways of selecting 3 men from 8 men

=  ^8C_3 = \frac{8!}{(8-3)!3!} = \frac{8!}{5!3!} = 56 ways

Number of ways of selecting 2 women from 10 men

=  ^{10}C_2 = \frac{10!}{(10-2)!2!} = \frac{10!}{8!2!} = 45 ways

Number of ways of selecting 3 men and 2 women = 56*45

Number of ways of selecting 3 men and 2 women = 2520

Probability of selecting 3 men and 2 women = 2520/8568 = 0.294

probability that a 5 member committee chosen randomly will have 3 men and 2 women = 0.294

6 0
3 years ago
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