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mr Goodwill [35]
2 years ago
7

Solve the following equation by Cramer's rule​

Mathematics
1 answer:
podryga [215]2 years ago
5 0

Answer:

All Indians are my brothers and sisters aur Cramer mera chacha hai

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What slope would a line have to be perpendicular to a line with a slope of 1/4 ?
denpristay [2]

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A line perpendicular to another has a slope that is the negative reciprocal of the slope of the other line. The negative reciprocal of the original line is –2, and is thus the slope of its perpendicular line.

Step-by-step explanation:

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What is 4(x+9) simplified
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Answer: 4x+36

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1- 4 times x=4x

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3- so it is 4x+36

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Solve the equations by substitution<br> Y=3x-4<br> Y=x+2
elena-14-01-66 [18.8K]

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2 years ago
Write an equation that is perpendicular to 3x - 6y=1 and contains the points (-3,7)
zmey [24]
(-3,7), \ \ \ 3x - 6y = 1   \  subtract  \ (-3x) \ from \ each \ side \\ \\ -6y = -3x + 1 \ divide \ each \term \ by \  (-6) \\ \\ y =  \frac{3} {6}x - \frac{1}{6}\\ \\ y =  \frac{1} {2}x - \frac{1}{6}\\ \\ The \ slope \ is :m _{1} =  \frac{1}{2} \\ \\ If \ m_{1} \ and \ m _{2} \ are \ the \ gradients \ of \ two \ perpendicular \\ \\ lines \ we \ have \ m _{1}*m _{2} = -1 \\\\\frac{1}{2}*m_{2}=-1&#10;

\frac{1}{2}*m_{2}=-1\ \ | \ multiply\ both\ sides\ by\ 2  \\\\m_{2}=-2 \\\\ Now \ your \ equation \ of \ line \ passing \ through \ (-3,7) would \ be: \\ \\ y=m_{2}x+b \\ \\7=(-2} )\cdot (-3) + b \\ \\ 7=6+b\\ \\ b=7-6\\ \\b=1 \\ \\ y =-2x +1


5 0
3 years ago
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