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alisha [4.7K]
1 year ago
4

Suppose, two objects attract each other with a gravitationalforce of 36 Newtons. If the mass of both objects was doubledand if t

he distance between the objects was doubled, thenwhat would be the new force of attraction between the twoobjects?
Mathematics
1 answer:
Gemiola [76]1 year ago
8 0

EXPLANATION

Given the Newton’s Law of universal Gravitation:

F=G\frac{m_1\cdot m_2}{r^2}

As the force is of 36 N, we can substitute It on the function:

F=G\frac{m_1\cdot m_2}{r^2}

If the mass of both objects is doubled, then the force will be stronger by a factor of 4:

F=G\frac{2m_1\cdot2m_2}{r^2}=G\frac{4m_1m_2}{r^2}

Also, if the distance between them is doubled, then we will get a factor of 4 as shown as follows:

F=G\frac{2m_1\cdot2m_2}{(2r)^2}=G\frac{4m_1m_2}{4r^2}

Then, simplifying both numbers 4, we can conclude that the force will be the same:

F=G\frac{2m_1\cdot2m_2}{(2r)^2}=G\frac{4m_1m_2}{4r^2}=G\frac{m_1m_2}{r^2}\text{ \lbrack{}Same expression\rbrack}

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Answer:

\sum_{i=1}^n x_i = 334

\sum_{i=1}^n y_i =611

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With these we can find the sums:

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=13970-\frac{334^2}{10}=2814.4

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}=26584-\frac{334*611}{10}=6176.6

And the slope would be:

m=\frac{6176.6}{2814.4}=2.195

Nowe we can find the means for x and y like this:

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And we can find the intercept using this:

b=\bar y -m \bar x=61.1-(2.195*33.4)=-12.213

So the line would be given by:

y=2.195 x -12.213

Step-by-step explanation:

The data given on this case is:

x: 14,12,20,16,46,23,48,50,55,50

y: 24,24,28,30,80,30,90,85,120,110

For this case we need to calculate the slope with the following formula:

m=\frac{S_{xy}}{S_{xx}}

Where:

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}

So we can find the sums like this:

\sum_{i=1}^n x_i = 334

\sum_{i=1}^n y_i =611

\sum_{i=1}^n x^2_i =13970

\sum_{i=1}^n y^2_i =51581

\sum_{i=1}^n x_i y_i =26584

With these we can find the sums:

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=13970-\frac{334^2}{10}=2814.4

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}=26584-\frac{334*611}{10}=6176.6

And the slope would be:

m=\frac{6176.6}{2814.4}=2.195

Nowe we can find the means for x and y like this:

\bar x= \frac{\sum x_i}{n}=\frac{334}{10}=33.4

\bar y= \frac{\sum y_i}{n}=\frac{611}{10}=61.1

And we can find the intercept using this:

b=\bar y -m \bar x=61.1-(2.195*33.4)=-12.213

So the line would be given by:

y=2.195 x -12.213

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