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joja [24]
3 years ago
10

What is 1 and 1/4, 3/2, 1 and 6/8. 1 whole from least to greatest?

Mathematics
1 answer:
Anastaziya [24]3 years ago
3 0
Answer: 1, 1&1/4, 3/2, 1&6/8
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A teacher surveyed her class to find out how many texts the students send in a week. She created this box plot to show the data
trapecia [35]
Show me the box plot.
3 0
3 years ago
Please help, At a festival 2/7th of the number of girls was equal to 3/5th of the number of boys.
fenix001 [56]

Answer:

465

Step-by-step explanation:

Let the number of girls at the festival be--------- g

Let the number of boys at the festival be---------b

The conditions are;

2/7 g = 3/5 b ---------------(i)

g-b= 165 ---------------------(ii)---------make g the subject of the expression

g= 165 +b---------------------(iii)--------use this equation in (i)

2/7 (165 +b)= 3/5 b -------multiply both sides by 7

7*2/7(165+b) =3/5*7 b

2(165+b)=21/5 b ------multiply both sides by 5

5*2(165+b) = 21/5*5*b

10(165+b) = 21 b -------open brackets

1650 +10 b = 21 b------collect like terms

1650 = 21 b- 10 b

1650 = 11 b -----divide both sides by 11

1650/11 = 11b/11

150 = b = number of boys

Using equation (ii) where g-b =165  ;  g-150 =165 , g= 165+150 =315 number of girls

Total number of children at the festival = 150+315 =465

7 0
3 years ago
A friend has a 85% average before the final exam for a course. That score includes everything but the final, which counts for 15
Arlecino [84]

Answer:

87.25%

Step-by-step explanation:

Data given in the question

Before the final exam for a course, the average percentage is 85%

The counting percentage of the course grade is 15%

So by considering the above information, the best course grade your friend is

= Average\ percentage\times remaining\ percentage + percentage\ value\times counting\ percentage= 0.85\times 0.85 + 100\%\times  0.15

= 0.7225 + 15

= 87.25%

The remaining percentage is come from

= 100% - 15%

= 85%

Hence, the best course grade is 87.25%

7 0
3 years ago
Read 2 more answers
What's the exact value of Cos105 degrees
Burka [1]

Answer:

0.2588190451

Have A Good Day!

6 0
3 years ago
- To approach the runway, a small plane must begin a 6° descent starting from a height of 1297 feet above the
Vladimir79 [104]

Step-by-step explanation:

Use the equation: sin(Theta)=opposite/ hypotenuse

X shows the how far from approach

so sin(26)=1297/x

rearrange to make: X=1125/sin(26

so 1125/sin(26)= 2,566.3 miles

Therefore, it will be 2,566.3 miles from approach

hope this helps :)

Have a nice day

4 0
3 years ago
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