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Lilit [14]
11 months ago
7

I need to find the simplest form of 88 ---- 90

Mathematics
1 answer:
hram777 [196]11 months ago
7 0

Given

\frac{88}{90}

So,

\frac{88}{90}=\frac{2\cdot44}{2\cdot45}=\frac{44}{45}

So, the simplest form of 88/90 is 44/45

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A physical trainer decides to collect data to see if people are actually weight changing weight during the shelter in place. He
telo118 [61]

Answer:

H0: µd = 0 (claim)

H1: µd ≠ 0

This is a two-tail t-test for µd

Step-by-step explanation:

This is a paired (dependent) sample test, with its hypothesis is written as :

H0: µd = 0

H1: µd ≠ 0

From the equality sign used in the hypothesis declaration, a not equal to ≠ sign in the alternative hypothesis is used for a two tailed t test

The data isn't attached, however bce the test statistic cannot be obtained. However, the test statistic formular for a paired sample is given as :

T = dbar / (Sd/√n)

dbar = mean of the difference ; Sd = standard deviation of the difference.

3 0
3 years ago
What is a domain? <br> What is a range?
lidiya [134]

Answer:

he domain of a function f(x) is the set of all values for which the function is defined, and the range of the function is the set of all values that f takes.

Step-by-step explanation:

:)

5 0
3 years ago
Find an explicit formula for f(n). ​
soldi70 [24.7K]

Answer:

f(n) = 2n - 2

Step-by-step explanation:

Given the recursive formula

f(n) = f(n - 1) + 2 with f(1) = 0, then

f(2) = f(1) + 2 = 0 + 2 = 2

f(3) = f(2) + 2 = 2 + 2 = 4

f(4) = f(3) + 2 = 4 + 2 = 6

The terms of the sequence are 0, 2, 4, 6, ....

These are the first 4 terms of an arithmetic sequence with explicit formula

f(n) = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here d = 2 - 0 = 4 - 2 = 6 - 4 = 2 and a₁ = 0, thus

f(n) = 0 + 2(n - 1), that is

f(n) = 2n - 2 ← explicit formula

5 0
3 years ago
PLEASE ANSWER AS SOON AS YOU SEE THIS
jeka57 [31]

Answer:2

Step-by-step explanation:

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What is 669.5554 written in word form
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I would have said six hundred thousand but that cant be it.. sorry
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