Http://prntscr.com/anjh06
The image I saw was a paper with 90° edges. the 90° was cut into 2, 75° and x.
x = 90° - 75° = 15°
Interior angles of a triangle should equal 180°. The other corner of the paper is part of the triangle. It has a measure of 90°
The two angles are 15° and 90°. To find the remaining unknown angle, we deduct the two angles from 180°
3rd angle = 180° - 15° - 90°
3rd angle = 180° - 105°
3rd angle = 75°
Binomial probability states that the probability of x successes on n repeated trials in an experiment which has two possible outcomes can be obtained by
(nCx).(p^x)⋅((1−p)^(n−x))
Where success on an individual trial is represented by p.
In the given question, obtaining heads in a trial is the success whose probability is 1/2.
Probability of 6 heads with 6 trials = (6C6).((1/2)^6).((1/2)^(6–6))
= 1/(2^6)
= 1/64
(4,12) is the correct answer
3 < 3x+6
-3<3x
-1<x
3x+6<24
3x<18
x<6
-1<x<6 the book is right
Answer:
165 combinations possible
Step-by-step explanation:
This is a combination problem as opposed to a permutation, because the order in which we fill these positions is not important. We are merely looking for how many ways each of these 11 people can be rearranged and matched up with different candidates, each in a different position each time. The formula can be filled in as follows:
₁₁C₃ = 
which simplifies to
₁₁C₃ = 
The factorial of 8 will cancel out in the numerator and the denominator, leaving you with
₁₁C₃ = 
which is 165
