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1 year ago

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Miles fills his gas tank with 6 gallons of unleaded gas for $26.58 . How much would it cost him to fill the tank with 18 gallons

?A) $4.06B) $78C) $35.85D) $79.74

1 answer:

borishaifa [10]1 year ago

6 0

We will caluclate the cost per gallon first. Then, we will multiply the new quantity by this cost, so we get the new cost.

As we are told that 6 gallons costs 26.58, we can divide 26.58 by 6 to calculate the cost per gallon. It would be

$\frac{26.58}{6}=4.43$

Now we multiply this quantity by 18, so we get the cost of 18 gallons. It would be

$4.43\cdot18=79.74$

so the cost of 18 gallons is 79.74

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A rectangle has length 72 cm and width 56 cm. The other rectangle has the same area as this one, but its width is 21 cm. What is

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The length of the rectangle is = 72 cm

The width of the rectangle is = 56 cm

Area of the rectangle is = $length*width$

= $72\times56=4032$ cm²

As given, the other rectangle has the same area as this one, but its width is 21 cm.

Let the length here be = x

$4032=x*21$

$x=\frac{4032}{21}=192$

Hence, length is 192 cm.

We can see that as width decreases, the length increases if area is constant and when length decreases then width increases if area is constant.

So, in the new rectangle,constant of variation=k is given by,

$\frac{192}{72}=\frac{8}{3}$ or $\frac{56}{21}=\frac{8}{3}$

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Okay so we have to first find the total.
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3 years ago

The population of a town is 6500 and is increasing at a rate of 4% each year. Create a function for this scenario. At this rate,

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Answer:

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Step-by-step explanation:

If the population increases at a rate of 4% per annum, then:

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Where $P_0$ is the initial population and $P_n$ is the population in year n

In year 2

$P_2 = P_1 + 0.04P_1$

It can also be written as:

$P_2 = P_0 + 0.04P_0 + 0.04 (P_0 + 0.04P_0)$

Taking out common factor $P_0$

$P_2 = (1 + 0.04) (P_0) + 0.04P_0 (1 + 0.04)$

Taking out common factor (1 + 0.04)

$P_2 = (1 + 0.04) (P_0 + 0.04P_0)$

Taking out again common factor $P_0$

$P_2 = (1 + 0.04) (1 + 0.04) P_0$

Simplifying

$P_2 = P_0 (1 + 0.04) ^ 2$

So

$P_n = P_0 (1 + 0.04) ^ n$

This is the equation that represents the population for year n

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