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White raven [17]
3 years ago
9

PLEASE HELP MEEEEEEEEEEEEEEEEEEE

Mathematics
1 answer:
pickupchik [31]3 years ago
8 0

This sequence be represented as a recursive equation by a1=8 and an=2a1

<u>Step-by-step explanation</u>:

  • 'Recursive' refers to the repetition of a specific process in a sequence.
  • The given sequence is {8,16,32,64}.
  • If the value is 2 times the previous value, then an=2a(n-1)

Let a1=8,

then a2 = 2a(2-1)

⇒ a2 = 2a1

⇒ a2 = 2(8)

⇒ a2 = 16

Similarly,

For a2=16,

⇒ a3 = 2(a2)

⇒ a3 = 2(16)

⇒ a3 = 32

For a3=32,

⇒ a4 = 2(a3)

⇒ a4 = 2(32)

⇒ a4 = 64

∴ The equation is recursive as a1=8 and an=2a1 to follow the sequence.

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The distribution of weights of potato chip bags filled off a production line is unknown. However, the mean is m=13.35 OZs and th
Nikitich [7]

Answer:

a) \mu_{\bar X} =13.35

e.none of the above

b) \sigma_{\bar X}= \frac{0.12}{\sqrt{36}}= 0.02

a.0.0200

c) z = \frac{13.32-13.35}{\frac{0.12}{\sqrt{36}}}= -1.5

P(\bar X< 13.32)= P(z

a.0.0668

d) z = \frac{13.30-13.35}{\frac{0.12}{\sqrt{36}}}= -2.5

z = \frac{13.36-13.35}{\frac{0.12}{\sqrt{36}}}= 0.5

P(13.30

c.0.6853

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

X \sim N(13.35,0.12)  

Where \mu=13.35 and \sigma=0.12

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

Part a

\mu_{\bar X} =13.35

Part b

\sigma_{\bar X}= \frac{0.12}{\sqrt{36}}= 0.02

Part c

We want this probability:

P(\bar X< 13.32)

For this case we can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And using this formula we got:

z = \frac{13.32-13.35}{\frac{0.12}{\sqrt{36}}}= -1.5

P(\bar X< 13.32)= P(z

Part d

We want this probability:

P(13.30

For this case we can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And using this formula we got:

z = \frac{13.30-13.35}{\frac{0.12}{\sqrt{36}}}= -2.5

z = \frac{13.36-13.35}{\frac{0.12}{\sqrt{36}}}= 0.5

P(13.30

8 0
3 years ago
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Metal strips 11 feet long and 2 feet wide . of the stripping costs $6 per foot , find the total costs
adoni [48]
The area of the metal strips:
A = L * W , where L stays for length and W stays for wirth.
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What is the prime factorization of 28 and 50?<br> Explain if possible.
dangina [55]

Answer:

prime factorization of 28

28 = 2 × 2 × 7

prime factorization of 50

50 = 2 × 5 × 5

Step-by-step explanation:

GCF, multiply all the prime factors common to both numbers:

Therefore, GCF = 2

3 0
2 years ago
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ArbitrLikvidat [17]
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