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3 years ago

Can someone explain how to do these thx

Mathematics

1 answer:

Monica [59]3 years ago

7 0

Answer:

i have made it in above picture

hope it helps

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Please help! Need to pass a module test!

slega [8]

-1 - 8 / 2 + 1 = -9 / 3 = -3

-1 = -3(2) + b
-1 = -6 + b
Add 6 to both sides.
5 = b

y = -3x + 5

5 0

3 years ago

Read 2 more answers

If there is a nonmathematical symbol in the preceding expression, then your browser doesn't have the math symbol font. Please fo

horrorfan [7]

Complete Question

The complete question is shown on the first uploaded image

Answer:

$g(h(x)) = \sqrt[4]{x^2 + x +5} + 3$

$h(g(x)) = \sqrt{x} + 7\sqrt[4]{x} + 17$

$h(h(x)) = [x^2 + x + 5 ]^2 + x^2 + x + 10$

Step-by-step explanation:

From the question we are told that

$h(x) = x^2 + x + 5$

and

$g(x) = \sqrt[4]{x} + 3$

Considering first question

Now we are told g(h(x))

i.e

$g(h(x)) = [x^2 + x + 5 ]^{\frac{1}{4} } + 3$

=> $g(h(x)) = \sqrt[4]{x^2 + x +5} + 3$

Considering second question

Now we are told h(g(x))

i.e

$h(g(x)) = [x^{\frac{1}{4} } + 3]^2 + x^{\frac{1}{4} } + 3 + 5$

=> $h(g(x)) = x^{\frac{1}{2} } + 6x^{\frac{1}{4} } + 9+ x^{\frac{1}{4}} + 8$

=> $h(g(x)) = x^{\frac{1}{2}} + 7x^{\frac{1}{4}} + 17$

=> $h(g(x)) = \sqrt{x} + 7\sqrt[4]{x} + 17$

Considering third question

$h(h(x))= [x^2 + x + 5]^2 + [x^2 + x + 5 ] + 5$

=> $h(h(x)) = [x^2 + x + 5 ]^2 + x^2 + x + 10$

8 0

4 years ago

-7b - 3 equals -3b + 5

ella [17]

Answer:

b= -8/5

Step-by-step explanation:

-5-3=7b-3b

-8=5b

b= -8/5

8 0

3 years ago

Find the dimensions of a triangle given the following information. The perimeter is equal to 36cm, side 1 is 4 less than side 2

kolezko [41]

Check the picture below.

so what are the lengths of the 1st and 3rd side anyway? well x - 4 and 2x.

4 0

4 years ago

Solve 6-x-3=4x-12 for x recording your steps as you work. Plz help

Nadya [2.5K]

The next ateo in orden to get the answer is -x-4x=-6-12
-5x=-18
X=3

4 0

3 years ago