Step-by-step explanation:
m < E = m < y
G I bisect < FGH
m < E = m < z ......Corresponding Position
EF |I Gl
< F = < z
< F = < y .............Alternatively
EF |I G[
Answer:
X = 60° (corresponding angles are equal )
<span>−6a + 6a + 5 = 8
5 = 8 False
So, </span><span>No solution.</span>
Answer:One solution was found : x = 12. Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the ...
Step-by-step explanation:
Answer:
Step-by-step explanation:
To prove Δ ABC similar to ΔDBE we can consider
Segments AC and DE are parallel.
⇒ DE intersects AB and BC in same ratio.
AB is a transversal line passing AC and DE.
⇒∠BAC=∠BDE [corresponding angles]
Angle B is congruent to itself due to the reflexive property.
All of them are telling a relation of parts of ΔABC to ΔDBE.
The only option which is not used to prove that ΔABC is similar to ΔDBE is the first option ,"The sum of angles A and B are supplementary to angle C".
