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Zepler [3.9K]
3 years ago
11

True / or / False2a2b2c2d

Mathematics
2 answers:
seropon [69]3 years ago
3 0
The second is true answer.
Good luck.
LekaFEV [45]3 years ago
3 0
Second:true hope it helped
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What is the answer to this math question
Vilka [71]

(19 {b}^{3}  + 16 {f}^{3} ) \times 2 {b}^{5}  = 38 {b}^{8}  + 32 {b}^{5}  {f}^{3}
8 0
3 years ago
PLZZ HELP <br> 2/3 divided by 5
melamori03 [73]

Answer:

2/15

Step-by-step explanation:

2/3 divided 5 is really just:

2/3*1/5

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7 0
3 years ago
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5 0
3 years ago
If a=(-1, -3) and b=(11, -8) what is the length of ab?
professor190 [17]

Answer: D.  The length is 13 units.

Step-by-step explanation:

(-1, -3 )    Find the difference between the x values and y values.

 (11, -8)  

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-1-11 =   -12    now find the  absolute values.

The absolute value of 5 is 5 .  The absolute value of  -12 is 12.

Now use the Pythagorean Theorem formula a^2 + b^2 =c^2  where c square is the length between AB.

5^2 + 13^2 = C^2

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8 0
3 years ago
I need help with this please its due today :(
yKpoI14uk [10]

Answer:

a) \ 6^2 \times 6^3 = 6^{2+3} = 6^5 = 7776\\\\b)\ \frac{(-3)^5 }{(-3)^2} = (-3)^{5-2} = (-3)^3 = -27\\\\c)\ [(-2)^3]^4 = (-2)^{3\times 4} = (-2)^{12} = 4096 \\\\d)\ (\frac{1}{999})^0 = 1,  anything \ raise \ to \ zero = 1\\\\e) \ (\frac{4}{3})^{-2} = 4^{-2} \times 3^2 = \frac{9}{16}\\\\f) \ \frac{2^5 \times 2^9}{2^{16}} = 2^{5+9-16} = 2^{-2} = \frac{1}{4}

4 0
3 years ago
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