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Liono4ka [1.6K]
1 year ago
5

Ayna and Leslie both simplified the expression. Which student is correct

Mathematics
1 answer:
Ne4ueva [31]1 year ago
6 0

Given:

\sqrt[]{18x^4y^5}

The expansion is,

\sqrt[]{18x^4y^5}=\sqrt[]{2\times3\times3\times x\times x\times x\times x\times y\times y\times y\times y\times y}

On simplification we get,

\begin{gathered} =\sqrt[]{2\times3^2\times x^2\times x^2\times y^2\times y^2\times y} \\ =3x^2y^2\sqrt[]{2y} \end{gathered}

Hence, Leslie was correct.

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