The slope of the line of best fit to the raw-score scatter plot is 0.98
- The equation is y = 0.98x - 3.74
- The value of y given that x = 12 is 8.02
<h3>How to determine the slope of the line?</h3>
From the question, we have the following parameters that can be used in our computation:
- Standard deviations of X, Sx = 1.88
- Standard deviations of Y, Sy =2.45
- Correlation coefficient, r between X and Y = 0.75
The slope (b) of the line is calculated as
b = r * Sy/Sx
Substitute the known values in the above equation, so, we have the following representation
b = 0.75 * 2.45/1.88
Evaluate
b = 0.98
<h3>The equation of the line of best fit</h3>
A linear equation is represented as
y = bx + c
Where
Slope = b
y-intercept = c
In (a), we have
b = 0.98
So, we have
y = 0.98x + c
Recall that the point (13, 9) is on the line of best fit.
So, we have
9 = 0.98 * 13 + c
This gives
9 = 12.74 + c
Evaluate
c = -3.74
So, we have
y = 0.98x - 3.74
<h3>The value of y from x</h3>
Here, we have
x = 12
So, we have
y = 0.98 x 12 - 3.74
Evaluate
y = 8.02
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143.7 I believe since you take 6.80*20=136+46=2.3*20
136+46=182
182*7.65%=168.08
168.08*8.95%=153.04
153.04*6.1%=143.7
Answer:
What are the angles I dont see them :/
Step-by-step explanation:
what are they
Translation rotation reflection
Given the angle:
-660°
Let's find the coterminal angle from 0≤θ≤360.
To find the coterminal angle, in the interval given, let's keep adding 360 degrees to the angle until we get the angle in the interval,
We have:
Coterminal angle = -660 + 360 = -300 + 360 = 60°
Therefore, the coterminal angle is 60°.
Since 60 degrees is between 0 to 90 degrees, is is quadrant I.
60 degrees lie in Quadrant I.
Also since it is in quadrant I, the reference angle is still 60 degrees.
ANSWER:
The coterminal angle is 60°, which lies in quadrant I, with a reference angle of 60°