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dimaraw [331]
4 years ago
6

What fraction of the original sample remains ?

Mathematics
1 answer:
Alexxandr [17]4 years ago
5 0
1.25×10^17 atoms are left after 1 hr and 45 mins.
1/32 remains out of the original sample
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I need help asapp!!!!!!!
labwork [276]

Answer:

Step-by-step explanation:

As per midsegment theorem of a trapezoid,

Segment joining the midpoints of the legs of the of the trapezoid is parallel to the bases and measure half of their sum.

Length of midsegment = \frac{1}{2}(b_1+b_2)

3). MN = \frac{1}{2}(18+10)

           = 14

4). MN = \frac{1}{2}(57+76)

           = 66.5

5). MN = \frac{1}{2}(AB+DC)

    7 = \frac{1}{2}(AB+10)

    14 = AB + 10

    AB = 14 - 10

    AB = 4

6). 15 = \frac{1}{2}[(3x+2)+(2x-2)]

    30 = 5x

     x = 6

4 0
2 years ago
Given the measures of three angles of a triangle, explain how to find the ratio of the lengths of two sides of the triangle.
pantera1 [17]

You can let the sides be a and b. You can then use the Law of Sines to create an equation relating the two sides and the angles opposite them, and finally isolate a/b.

8 0
1 year ago
What is 3/5 divided by 1/2 using the keep change flip method
goblinko [34]

Answer:

6/5

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Is this true or false?​
Mashcka [7]

Answer:

true

Step-by-step explanation:

one tree has 13 apples

8 0
2 years ago
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Imagine that you need to compute e^0.4 but you have no calculator or other aid to enable you to compute it exactly, only paper a
labwork [276]

Answer:

0.0032

Step-by-step explanation:

We need to compute e^{0.4} by the help of third-degree Taylor polynomial that is expanded around at x = 0.

Given :

e^{0.4} < e < 3

Therefore, the Taylor's Error Bound formula is given by :

$|\text{Error}| \leq \frac{M}{(N+1)!} |x-a|^{N+1}$   , where $M=|F^{N+1}(x)|$

         $\leq \frac{3}{(3+1)!} |-0.4|^4$

         $\leq \frac{3}{24} \times (0.4)^4$

         $\leq 0.0032$

Therefore, |Error| ≤ 0.0032

4 0
3 years ago
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