The formula for the volume of a cube is:
V = a^3
Plug in what we know:
125 = a^3
Cube the other side:
![a = \sqrt[3]{125}](https://tex.z-dn.net/?f=a%20%3D%20%5Csqrt%5B3%5D%7B125%7D%20)
The answer is = (x + 5y) (x + 7y)
Break the expression into two groups.
x^2 + 12xy + 35y^2
(x^2 + 5xy) (7xy + 35^2)
Factor out x from x^2 + 5xy: x(x + 5y)
Factor out 7y from 7xy + 35y^2: 7y(x + 5y)
=x(x + 5y) + 7y(x + 5y)
Next, factor out the common term (x+ 5y).
Answer = (x + 5y) (x + 7y)
x+(x+8)+(x+100)=750
3x+108=750
3x=642
x=214
So your numbers are 214, 222 and 314
<span>Answer:
Its too long to write here, so I will just state what I did.
I let P=(2ap,ap^2) and Q=(2aq,aq^2)
But x-coordinates of P and Q differ by (2a)
So P=(2ap,ap^2) BUT Q=(2ap - 2a, aq^2)
So Q=(2a(p-1), aq^2)
which means, 2aq = 2a(p-1)
therefore, q=p-1
then I subbed that value of q in aq^2
so Q=(2a(p-1), a(p-1)^2)
and P=(2ap,ap^2)
Using these two values, I found the midpoint which was:
M=( a(2p-1), [a(2p^2 - 2p + 1)]/2 )
then x = a(2p-1)
rearranging to make p the subject
p= (x+a)/2a</span>
So to solve problems like these you can work out each equation by substituting the x and y with the coords from the vertex (2,-4) and which ever one is true is the corresponding equation.
Lets try the first one
A) y = 2( x-2)^2-4 this would become
-4 = 2(2-2)^2-4 we solve this and get
-4 = 2(0)-4
-4 = -4
so it seems like A is the correct answer, of course we'd wanna check out the other answers just to be sure.
Lets try one and do C
C) -2 = 2(-4-2)^2+2
-2 = 2(-8)^2+2
-2 = 130
These aren't equal so this can't be our equation
So you can also do one more just to be super sure you have the right answer but I think A is the correct one :)
