Question

I'm doing quadratic equations and I keep getting stuck I will include a picture

Answer 1

Given:

$6h^9=12h^8$

Solving the above equation, we have:

$\begin{gathered} 6h^9-12h^8=0 \\ 6h^8(h-2)=0 \end{gathered}$

Now if the product of two numbers is zero then either of the two numbers is zero or both are zero, so,

$\begin{gathered} 6h^8=0\text{ or (h-2)=0} \\ \end{gathered}$

So,

$\begin{gathered} h^8=0\text{ or h=2} \\ h=\text{ 0, 0, 0, 0, 0, 0, 0, 0, 2} \end{gathered}$

So , h= 0, 0, 0,0 ,0 , 0 , 0, 0 ,2