a. How many quarts did they make is 25 quarts of lemonade
b. How much money will they make if they sell it all is $62.50
a. Calculation to determine How many quarts did they make.
Given: 1 gallon =5 quarts
Hence:
5 gallons of lemonade=5×5 quarts of lemonade
5 gallons of lemonade=25 quarts of lemonade
b. Calculation to determine how much money will they make if they sell it all
Given: 1 quarts=$2.50
Hence:
25 quarts=25 ×$2.50
25 quarts=$62.50
Inconclusion:
a. How many quarts did they make is 25 quarts of lemonade
b. How much money will they make if they sell it all is $62.50
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Answer:
-8π or -25.13
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
first look at all the numbers in the relation.then since inverse means opposite find the answers where the numbers in the parenthesis are in the opposite order than the question. Finally look for the answer In which all the positive numbers in the parenthesis(in the given relation) are negative (on the answers)and the negative numbers (in the given relation) are positive (on the answers).
Answer:
blue = 35
green = 29
red = 38
Step-by-step explanation:
Let r = red
Let g = green
let b = blue
r + g + b = 102
r = b + 3
b = g + 6 Subtract 6 from both sides of the equation
b - 6 = g
===================
substitute for red and green
(b + 3) + b + b - 6 = 102
b + 3 + b + b - 6 = 102
Combine like terms
3b - 3 = 102
Add 3 to both sides
3b - 3 + 3 = 102 + 3
3b = 105
Divide by 3
3b/3 = 105/3
b = 35
======================
r = b + 3
r = 35 + 3
r = 38
=======================
g = b - 6
g = 35 - 6
g = 29
========================
As we know that the standard equation of circle is 
, where <em>r</em> is the radius of circle and centre at <em>(h,k) </em>
Now , as the circle passes through <em>(2,9)</em> so it must satisfy the above equation after putting the values of <em>h</em> and <em>k</em> respectively
After raising ½ power to both sides , we will get <em>r = +5 , -5</em> , but as radius can never be -<em>ve</em> . So <em>r = +</em><em>5</em><em> </em>
Now , putting values in our standard equation ;
<em>This is the required equation of </em><em>Circle</em>
Refer to the attachment as well !
